我有一个 MongoDB 数据库,我存储了所有图片,当我检索它们时,我存储了一些双打,这不是很好,但无论如何我想只显示不同的元素。
@foreach (Foto f in fotos.Distinct(new IEqualityComparer<Foto> { )
但是Foto类有一个名为smallurl的属性,我想通过这个属性只显示不同的元素。那么如何编写自定义 IEqualityComparer 。
答案 0 :(得分:2)
var listOfUrls = fotos.Select(f => f.smallurl).Distinct();
编辑专门回答您的问题
从搜索c#IEqualityComparer http://msdn.microsoft.com/en-us/library/ms132151.aspx
的MSDN文档中实际复制过来class FotoEqualityComparer : IEqualityComparer<Foto>
{
public bool Equals(Foto f1, Foto f2)
{
return f1.smallurl == f2.smallurl;
}
public int GetHashCode(Foto f)
{
return f.smallurl.GetHashCode();
}
}
@foreach (Foto f in fotos.Distinct(new FotoEqualityComparer() )
答案 1 :(得分:2)
实际上很容易。只需为您的方法提供一个独特的选择器,如下所示:
public static IEnumerable<TSource> DistinctBy<TSource, TResult>(this IEnumerable<TSource> enumerable, Func<TSource, TResult> keySelector)
{
Dictionary<TResult, TSource> seenItems = new Dictionary<TResult, TSource>();
foreach (var item in enumerable)
{
var key = keySelector(item);
if (!seenItems.ContainsKey(key))
{
seenItems.Add(key, item);
yield return item;
}
}
}
或者,您可以创建另一个以实现IEquality比较器的通用实现:
public static IEnumerable<TSource> DistinctBy<TSource>(this IEnumerable<TSource> enumerable, Func<TSource, TSource, bool> equalitySelector, Func<TSource, int> hashCodeSelector)
{
return enumerable.Distinct(new GenericEqualitySelector<TSource>(equalitySelector, hashCodeSelector));
}
class GenericEqualitySelector<TSource> : IEqualityComparer<TSource>
{
public Func<TSource, TSource, bool> _equalityComparer = null;
public Func<TSource, int> _hashSelector = null;
public GenericEqualitySelector(Func<TSource, TSource, bool> selector, Func<TSource, int> hashSelector)
{
_equalityComparer = selector;
_hashSelector = hashSelector;
}
public bool Equals(TSource x, TSource y)
{
return _equalityComparer(x, y);
}
public int GetHashCode(TSource obj)
{
return _hashSelector(obj);
}
}
答案 2 :(得分:1)
从MSDN修改
public class MyEqualityComparer : IEqualityComparer<Foto>
{
public bool Equals(Foto x, Foto y)
{
//Check whether the compared objects reference the same data.
if (Object.ReferenceEquals(x, y)) return true;
//Check whether any of the compared objects is null.
if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null))
return false;
//Check whether the foto's properties are equal.
return x.smallurl == y.smallurl ;
}
// If Equals() returns true for a pair of objects
// then GetHashCode() must return the same value for these objects.
public int GetHashCode(Foto foto)
{
//Check whether the object is null
if (Object.ReferenceEquals(foto, null)) return 0;
//Get hash code for the foto.smallurl field if it is not null.
return foto.smallurl == null ? 0 : foto.smallurl.GetHashCode();
}
}
答案 3 :(得分:1)
创建自己的:
public class FotoEqualityComparer : IEqualityComparer<Foto>
{
public bool Equals(Foto x, Foto y)
{
return x.smallurl.Equals(y.smallurl);
}
public int GetHashCode(Foto foto)
{
return foto.smallurl.GetHashCode();
}
}
并像这样使用它:
fotos.Distinct(new FotoEqualityComparer());
修改强>
.Distinct()没有内联lambda重载,因为当两个对象比较相等时,它们必须具有相同的GetHashCode返回值(否则Distinct内部使用的哈希表将无法正常运行)。
但是如果你想要它在一行中,那么你也可以进行分组以获得相同的结果:
fotos.GroupBy(f => f.smallurl).Select(g => g.First());
答案 4 :(得分:1)
使用GroupBy的代码更简单:
@foreach (Foto f in fotos.GroupBy(f => f.smallurl).Select(g => g.First()))
答案 5 :(得分:0)
您应该创建自己的EqulityComparer:
class FotoEqualityComparer : IEqualityComparer<Foto>
{
public bool Equals(Foto b1, Foto b2)
{
if (b1.smallurl == b2.smallurl)
return true;
else
return false;
}
public int GetHashCode(Foto bx)
{
int hCode = bx.smallurl ;
return hCode.GetHashCode();
}
}