Question

我在某些地方有4个不同的文件，例如： d：\ 1.txt的 d：\ 2.txt D：\ 3.txt和 d：\ 4.txt

我需要创建一个新文件 NewFile.txt ，它应该包含上述文件中存在的所有内容1.txt，2.txt，3.txt 4.txt ... ....

所有数据都应出现在New Single文件（NewFile.txt）中..

请建议我在java或Groovy中做同样的事情......

Answer 1

以下是在Groovy中执行此操作的一种方法：

// Get a writer to your new file
new File( '/tmp/newfile.txt' ).withWriter { w ->

  // For each input file path
  ['/tmp/1.txt', '/tmp/2.txt', '/tmp/3.txt'].each { f ->

    // Get a reader for the input file
    new File( f ).withReader { r ->

      // And write data from the input into the output
      w << r << '\n'
    }
  }
}

以这种方式执行此操作（在每个源文件上调用getText）的优点是，在将其内容写入newfile之前，不需要将整个文件加载到内存中。如果您的某个文件非常庞大，另一种方法可能会失败。

Answer 2

这是groovy

def allContentFile = new File("D:/NewFile.txt")
def fileLocations = ['D:/1.txt' , 'D:/2.txt' , 'D:/3.txt' , 'D:/4.txt']
fileLocations.each{ allContentFile.append(new File(it).getText()) }

Answer 3

我尝试解决这个问题，如果将内容复制到数组并将数组写入其他文件，我发现它很容易

public class Fileread 
{

public static File read(File f,File f1) throws FileNotFoundException
{

    File file3=new File("C:\\New folder\\file3.txt");
    PrintWriter output=new PrintWriter(file3);
    ArrayList arr=new ArrayList();
    Scanner sc=new Scanner(f);
    Scanner sc1=new Scanner(f1);
    while(sc.hasNext())
    {
        arr.add(sc.next());

    }
     while(sc1.hasNext())
    {
        arr.add(sc1.next());

    }
       output.print(arr);
   output.close();

    return file3;
}
/**
 *
 * @param args
 * @throws FileNotFoundException
 */
public static void main(String[] args) {
    try
    {
   File file1=new File("C:\\New folder\\file1.txt");
   File file2=new File("C:\\New folder\\file2.txt");
   File file3=read(file1,file2);
   Scanner sc=new Scanner(file3);
   while(sc.hasNext())
       System.out.print(sc.next());

    }
    catch(Exception e)
    {
        System.out.printf("Error  :%s",e);
    }
}
}

Answer 4

我告诉你在java中完成它的方式：

public class Readdfiles {
  public static void main(String args[]) throws Exception
  {
    String []filename={"C:\\WORK_Saurabh\\1.txt","C:\\WORK_Saurabh\\2.txt"};
    File file=new File("C:\\WORK_Saurabh\\new.txt");
    FileWriter output=new FileWriter(file);
    try
    {   
      for(int i=0;i<filename.length;i++)
      {
        BufferedReader objBufferedReader = new BufferedReader(new FileReader(getDictionaryFilePath(filename[i])));

        String line;
        while ((line = objBufferedReader.readLine())!=null )
        {
          line=line.replace(" ","");

          output.write(line);
        }
        objBufferedReader.close();
      }
      output.close();
    }
    catch (Exception e) 
    {
      throw new Exception (e);
    }
  }

  public static String getDictionaryFilePath(String filename) throws Exception
  {
    String dictionaryFolderPath = null;
    File configFolder = new File(filename);
    try 
    {
      dictionaryFolderPath = configFolder.getAbsolutePath();
    } 
    catch (Exception e) 
    {
      throw new Exception (e);
    }
    return dictionaryFolderPath;
  }
}

告诉我你是否有任何疑问

Answer 5

你可以在Java中做这样的事情。希望它可以帮助您解决问题：

import java.io.*;
class FileRead {
public void readFile(String[] args) {
for (String textfile : args) {

try{
      // Open the file that is the first 
      // command line parameter
      FileInputStream fstream = new FileInputStream(textfile);
      // Get the object of DataInputStream
      DataInputStream in = new DataInputStream(fstream);
      BufferedReader br = new BufferedReader(new InputStreamReader(in));
      String strLine;
      //Read File Line By Line
      while ((strLine = br.readLine()) != null)   {
      // Print the content on the console
      System.out.println (strLine);

    // Write to the new file
      FileWriter filestream = new FileWriter("Combination.txt",true);
      BufferedWriter out = new BufferedWriter(filestream);
      out.write(strLine);
      //Close the output stream
      out.close();

      }
      //Close the input stream
      in.close();
        }catch (Exception e){//Catch exception if any
      System.err.println("Error: " + e.getMessage());
      }
}
}

 public static void main(String args[]) {
 FileRead myReader = new FileRead();
 String fileArray[] = {"file1.txt", "file2.txt", "file3.txt", "file4.txt"};
    myReader.readFile(fileArray);

  }
}

Answer 6

一个班轮示例：

def out = new File(".all_profiles")
['.bash_profile', '.bashrc', '.zshrc'].each {out << new File(it).text}

OR

['.bash_profile', '.bashrc', '.zshrc'].collect{new File(it)}.each{out << it.text}

如果您有大文件，Tim的实施会更好。

Answer 7

vRow(1) = Format(vRow(1), "0000000") 'format first column (1 = first column; 2 = second column; etc ... )

将多个文件合并为一个

7 个答案: