Question

在字符串中搜索给定模式并在不使用awk的情况下回显它的最佳方式（在bash中）是什么？我想使用标准命令，例如grep，cat，cut或sed。

示例：

我想从lspci命令的输出中删除所有USB控制器的设备地址：

[artlab@localhost ~]$ lspci

00:00.0 Host bridge: Intel Corporation Core Processor DRAM Controller (rev 18)
00:1a.0 USB controller: Intel Corporation 5 Series/3400 Series Chipset USB2 Enhanced Host Controller (rev 05)
00:1c.0 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 1 (rev 05)
00:1c.4 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 5 (rev 05)
00:1c.5 PCI bridge: Intel Corporation 5 Series/3400 Series Chipset PCI Express Root Port 6 (rev 05)
00:1d.0 USB controller: Intel Corporation 5 Series/3400 Series Chipset USB2 Enhanced Host Controller (rev 05)
00:1e.0 PCI bridge: Intel Corporation 82801 PCI Bridge (rev a5)
00:1f.0 ISA bridge: Intel Corporation 3400 Series Chipset LPC Interface Controller (rev 05)
00:1f.2 RAID bus controller: Intel Corporation 82801 SATA Controller [RAID mode] (rev 05)
00:1f.3 SMBus: Intel Corporation 5 Series/3400 Series Chipset SMBus Controller (rev 05)
02:00.0 Ethernet controller: Intel Corporation 82574L Gigabit Network Connection
03:00.0 Ethernet controller: Intel Corporation 82574L Gigabit Network Connection
04:03.0 VGA compatible controller: Matrox Graphics, Inc. MGA G200eW WPCM450 (rev 0a)

我想检索（打印出）两个字符串：

00:1a.0
00:1d.0

Answer 1

我想知道谁会提出更多可能性。

lspci | grep 'USB Controller' | sed "s/ .*//"
lspci | grep 'USB Controller' | grep -o '^[^ ]*'
lspci | grep 'USB Controller' | while read id rest ; do echo $id ; done
lspci | grep 'USB Controller' | cut -f 1 -d ' '

Answer 2

sed -n '/USB controller/{s/ .*//;p}'

Answer 3

lspci | grep 'USB Controller' | cut -d' ' -f1

在bash中搜索并回显一部分字符串

3 个答案: