我有issues updating my database
。我创建了一个应用customers name, phone, email, their computer details and the services
的应用程序。我想更新他们但我遇到了一些麻烦。我将数据插入数据库的方式是这样的。
private void btnCreate_Click(object sender, EventArgs e)
{
//string connString = "server=localhost;uid=*****;password=********;database=dbomonkworksinfo;";
MySqlConnection conn = new MySqlConnection("server=localhost;uid=******;password=********;database=dbomonkworksinfo;");
conn.Open();
try
{
MySqlCommand command = new MySqlCommand("Insert into tserviceinfo (First_Name, Last_Name, Date, Phone, Email, Tech, Brand, Model, OS, Type, PC_Issue) values (?First_Name, ?Last_Name, ?Date, ?Phone, ?Email, ?Tech, ?Brand, ?Model, ?OS, ?Type, ?PC_Issue)", conn);
command.Parameters.AddWithValue("?First_Name", tbFirstName.Text);
command.Parameters.AddWithValue("?Last_Name", tbLastName.Text);
command.Parameters.AddWithValue("?Date", tbDate.Text);
command.Parameters.AddWithValue("?Phone", tbPhone.Text);
command.Parameters.AddWithValue("?Email", tbEmail.Text);
command.Parameters.AddWithValue("?Tech", tbTech.Text);
command.Parameters.AddWithValue("?Brand", tbBrand.Text);
command.Parameters.AddWithValue("?Model", tbModel.Text);
command.Parameters.AddWithValue("?OS", tbOS.Text);
command.Parameters.AddWithValue("?PC_Issue", tbIssue.Text);
command.Parameters.AddWithValue("?Services", lvOrdered.Items);
if (rbDesktop.Checked)
{
command.Parameters.AddWithValue("?Type", "Desktop");
}
else if (rbNotebook.Checked)
{
command.Parameters.AddWithValue("?Type", "Notebook");
}
/** MySqlCommand command2 = new MySqlCommand("Insert into tpcinfo (Brand, Model, OS, PC_Issue, Services) values (?Brand, ?Model, ?OS, ?PC_Issue, ?Services)", conn);
command2.Parameters.AddWithValue("?Brand", tbBrand.Text);
command2.Parameters.AddWithValue("?Model", tbModel.Text);
command2.Parameters.AddWithValue("?OS", tbOS.Text);
command2.Parameters.AddWithValue("?PC_Issue", tbIssue.Text);
command2.Parameters.AddWithValue("?Services", lvOrdered.Items);
* Changed to only one table. No one besides me sees the behind the program.
* **/
//command2.Parameters.AddWithValue("?type", SqlDbType.NVarChar).Value = type;
command.ExecuteNonQuery();
conn.Close();
tbFirstName.Clear();
tbLastName.Clear();
tbDate.Clear();
tbEmail.Clear();
tbBrand.Clear();
tbIssue.Clear();
tbTech.Clear();
tbModel.Clear();
tbPhone.Clear();
tbOS.Clear();
lvOrdered.Items.Clear();
lblPrice.Text = "$0.00";
}
catch (MySqlException ex)
{
MessageBox.Show("Can't connect to database\n" + ex.ToString());
}
}
我的问题确实是,how would I write an update statement?
我已经在网上看了,但是我无法适应我的需要而且我正在画一个空白。我正在研究这个程序非常不变但是我已经停了好几个月了,现在我真的画了一个空白。任何帮助将不胜感激!我能够查看输入的数据,但现在更新是下一步!谢谢!
答案 0 :(得分:1)
就这么简单,
UPDATE tserviceinfo
SET First_Name = ?First_Name,
Last_Name = ?Last_Name,
Date = ?Date,
Phone = ?Phone,
Email = ?Email,
Tech = ?Tech,
Brand = ?Brand,
Model = ?Model,
OS = ?OS,
Type = ?Type
// WHERE condition here