Question

是否有可能以某种方式修改它以便它可以找到类 class1 * OR * class class2 的表？

Info = soup.find('table', {'class' :'class1'})

Answer 1

find_all(self, name=None, attrs={}, recursive=True, text=None, limit=None, **kwargs) 

    Extracts a list of Tag objects that match the given
    criteria.  You can specify the name of the Tag and any
    attributes you want the Tag to have.

    The value of a key-value pair in the 'attrs' map can be a
    string, a list of strings, a regular expression object, or a
    callable that takes a string and returns whether or not the
    string matches for some custom definition of 'matches'. The
    same is true of the tag name.

例如：

>>> from bs4 import BeautifulSoup
>>> text = ''.join('<table class="class{}"></table>'.format(i) for i in range(10))
>>> soup = BeautifulSoup(text)
>>> 
>>> soup.find_all("table", {"class": ["class1", "class7"]})
[<table class="class1"></table>, <table class="class7"></table>]
>>> import re
>>> soup.find_all("table", {"class": re.compile("class[17]")})
[<table class="class1"></table>, <table class="class7"></table>]
>>> 
>>> soup.find_all("table", {"class": lambda x: 3*int(x[-1])**2-24*int(x[-1])+17 == -4})
[<table class="class1"></table>, <table class="class7"></table>]

[好吧，最后一个匹配太多，但你明白了：任何bool返回匹配函数都可以。]

检查类是否与两个字符串中的一个相等

1 个答案: