Zend喜欢或者条件

时间:2012-10-24 20:44:19

标签: zend-framework zend-db

我在条件中得到了sql问题:

$select->where('(users.user_fname LIKE (?) )','%'.$first.'%');

如何输入或条件使它看起来像:

$select->where('(users.user_fname LIKE (?) )','%'.$first.'%');
OR
$select->where('(users.user_fname LIKE (?) )','%'.$last.'%');

1 个答案:

答案 0 :(得分:1)

http://framework.zend.com/manual/1.12/en/zend.db.select.html

$select
    ->where('(users.user_fname LIKE "%?%")', $first)
    ->orWhere('(users.user_fname LIKE "%?%")', $last)
;