Question

我正在使用android-async-http而且非常喜欢它。我遇到了POST数据的问题。我必须按以下格式将数据发布到API： -

<request>
  <notes>Test api support</notes>
  <hours>3</hours>
  <project_id type="integer">3</project_id>
  <task_id type="integer">14</task_id>
  <spent_at type="date">Tue, 17 Oct 2006</spent_at>
</request>

根据文档，我尝试使用RequestParams来做，但它失败了。这是其他任何方式吗？我也可以发布等效的JSON。有什么想法吗？

Answer 1

Loopj POST示例 - 从他们的Twitter示例扩展：

private static AsyncHttpClient client = new AsyncHttpClient();

通过RequestParams正常发布：

RequestParams params = new RequestParams();
params.put("notes", "Test api support"); 
client.post(restApiUrl, params, responseHandler);

发布JSON：

JSONObject jsonParams = new JSONObject();
jsonParams.put("notes", "Test api support");
StringEntity entity = new StringEntity(jsonParams.toString());
client.post(context, restApiUrl, entity, "application/json",
    responseHandler);

Answer 2

@Timothy的回答对我不起作用。

我定义Content-Type的{{1}}以使其有效：

StringEntity

祝你好运：）

Answer 3

发布json的更好方法

RequestParams params = new RequestParams();
    params.put("id", propertyID);
    params.put("lt", newPoint.latitude);
    params.put("lg", newPoint.longitude);
    params.setUseJsonStreamer(true);

    ScaanRestClient restClient = new ScaanRestClient(getApplicationContext());
    restClient.post("/api-builtin/properties/v1.0/edit/location/", params, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(int statusCode, Header[] headers, byte[] responseBody) {
        }

        @Override
        public void onFailure(int statusCode, Header[] headers, byte[] responseBody, Throwable error) {
        }
    });

Answer 4

发布XML

protected void makePost() {
    AsyncHttpClient client = new AsyncHttpClient();
    Context context = this.getApplicationContext();
    String  url = URL_String;
    String  xml = XML-String;
    HttpEntity entity;
    try {
        entity = new StringEntity(xml, "UTF-8");
    } catch (IllegalArgumentException e) {
        Log.d("HTTP", "StringEntity: IllegalArgumentException");
        return;
    } catch (UnsupportedEncodingException e) {
        Log.d("HTTP", "StringEntity: UnsupportedEncodingException");
        return;
    }
    String  contentType = "string/xml;UTF-8";

    Log.d("HTTP", "Post...");
    client.post( context, url, entity, contentType, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(String response) {
            Log.d("HTTP", "onSuccess: " + response);
        }
          ... other handlers
    });
}

Answer 5

只需将您的xml或json写入字符串并使用正确的标头或不使用发送到服务器。并将“Content-Type”设置为“application / json”

Answer 6

如果某人遇到httpclient发送为Content-Type: text/plain的问题，请参阅此链接：https://stackoverflow.com/a/26425401/361100

loopj httpclient有些改变（或有问题），无法覆盖StringEntity原生内容类型为application/json。

Answer 7

您可以将JSON字符串添加为某种类型的InputStream - 我已经使用了ByteArrayStream，然后将其传递给RequestParams，您应该设置correctMimeType

InputStream stream = new ByteArrayInputStream(jsonParams.toString().getBytes(Charset.forName("UTF-8")));
multiPartEntity.put("model", stream, "parameters", Constants.MIME_TYPE_JSON);

Answer 8

只需创建JSONObject，然后将其转换为String“someData”，然后使用“ByteArrayEntity”发送

    private static AsyncHttpClient client = new AsyncHttpClient();
    String someData;
    ByteArrayEntity be = new ByteArrayEntity(someData.toString().getBytes());
    client.post(context, url, be, "application/json", responseHandler);

这对我来说很好。

Answer 9

将xml文件发布到php服务器：

public class MainActivity extends AppCompatActivity {

/**
 * Send xml file to server via asynchttpclient lib
 */

Button button;
String url = "http://xxx/index.php";
String filePath = Environment.getExternalStorageDirectory()+"/Download/testUpload.xml";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    button = (Button)findViewById(R.id.button);

    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            postFile();
        }
    });
}

public void postFile(){

    Log.i("xml","Sending... ");

    RequestParams params = new RequestParams();

    try {
        params.put("key",new File(filePath));
    }catch (FileNotFoundException e){
        e.printStackTrace();
    }

    AsyncHttpClient client = new AsyncHttpClient();

    client.post(url, params, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(int i, cz.msebera.android.httpclient.Header[] headers, byte[] bytes) {
            Log.i("xml","StatusCode : "+i);
        }

        @Override
        public void onFailure(int i, cz.msebera.android.httpclient.Header[] headers, byte[] bytes, Throwable throwable) {
            Log.i("xml","Sending failed");
        }

        @Override
        public void onProgress(long bytesWritten, long totalSize) {
            Log.i("xml","Progress : "+bytesWritten);
        }
    });
}

}

将android-async-http-1.4.9.jar添加到android studio后，去build.gradle并添加：依赖项下的compile 'com.loopj.android:android-async-http:1.4.9'

在AndroidManifest.xml上添加：

<uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" />

使用android-async-http（loopj）发布JSON / XML

9 个答案: