Question

我需要在服务器上传文件（具有不同的扩展名，即.txt，.jpg，.pdf ....）。我创建了一个接受http请求的站点，将虚拟目录映射到物理目录。所有thi在dowload中工作正常，现在我必须实现上传。

这是我的代码

private void UploadFile(string uploadFileName, string localFileName)
    {
        //long length = 0;
        string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x");
        HttpWebRequest httpWebRequest2 = (HttpWebRequest)WebRequest.Create(uploadFileName);
        httpWebRequest2.ContentType = "multipart/form-data; boundary=" + boundary;
        httpWebRequest2.Method = "POST";
        httpWebRequest2.KeepAlive = true;
        httpWebRequest2.Credentials = new NetworkCredential("USER", "PASSWORD", "DOMAIN"); 

        Stream memStream = new System.IO.MemoryStream();

        byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" +boundary + "\r\n");

        string formdataTemplate = "\r\n--" + boundary +"\r\nContent-Disposition: form-data; name=\"{0}\";\r\n\r\n{1}";

        memStream.Write(boundarybytes, 0, boundarybytes.Length);

        string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\n Content-Type: application/octet-stream\r\n\r\n";

        string header = string.Format(headerTemplate, "uplTheFile", localFileName);

        byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);

        memStream.Write(headerbytes, 0, headerbytes.Length);

        FileStream fileStream = new FileStream(localFileName, FileMode.Open, FileAccess.Read);
        byte[] buffer = new byte[1024];

        int bytesRead = 0;

        while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
        {
            memStream.Write(buffer, 0, bytesRead);
        }

        memStream.Write(boundarybytes, 0, boundarybytes.Length);

        fileStream.Close();

        httpWebRequest2.ContentLength = memStream.Length;

        Stream requestStream = httpWebRequest2.GetRequestStream();
        //error returned in lenght field: "This stream does not support seek operations."

        memStream.Position = 0;
        byte[] tempBuffer = new byte[memStream.Length];
        memStream.Read(tempBuffer, 0, tempBuffer.Length);
        memStream.Close();
        requestStream.Write(tempBuffer, 0, tempBuffer.Length);
        requestStream.Close();

        WebResponse webResponse2 = httpWebRequest2.GetResponse();
        //error returned from getResponse: "The remote server returned an error: (405) Method Not Allowed."
        //I guess cause my folder is in read only

        Stream stream2 = webResponse2.GetResponseStream();
        StreamReader reader2 = new StreamReader(stream2);

        MessageBox.Show(reader2.ReadToEnd());

        webResponse2.Close();
        httpWebRequest2 = null;
        webResponse2 = null; 

    }

首先我收到此错误：远程服务器返回错误：（405）方法不允许。所以我尝试通过在网站上添加映射来启用POST。

现在在te服务器上的文件夹中我有一个web.config文件：

    <?xml version="1.0" encoding="UTF-8"?>
 <configuration>
    <system.webServer>
    <directoryBrowse enabled="true" />
    <handlers>
        <add name="File TXT" path="*.*" verb="*" modules="IsapiModule" scriptProcessor="C:\Windows\System32\inetsrv\asp.dll" resourceType="Unspecified" requireAccess="Script" preCondition="bitness64" />
    </handlers>
</system.webServer>
</configuration>

以这种方式我没有得到任何错误，但应用程序不上传任何文件。我该如何解决这个问题？

Answer 1

更简单的解决方案是使用System.Net.Webclient类上传文件。

System.Net.WebClient client = new System.Net.WebClient();

client.UploadFile("www.myfileuploadendpoint.com",@"c:\myfiletoupload.txt");

客户端还有一个OnUploadFileCompleted事件，该事件将在完成时调用处理程序。

client.OnUploadFileCompleted  += UploadCompleted(sender,args) => { //do whatever you want}

这将为您节省代码和错误。祝好运！：）

Answer 2

上述两个样本均无效，

“远程服务器返回错误：（405）方法不允许。”是尝试上述代码时遇到的例外

期待有人分享他们对这些例外的想法，请。

RGDS，瑟尔

在httpwebrequest文件上传中启用POST

2 个答案: