Question

嗨，我有一个mysql查询，它将以最大状态计数返回post_id，它当前显示的结果是

POST_ID

    3

Mysql表：

(`post_id`, `user_id`, `status`, `date_created`)
(2, 2, 'funny', 20121022120627)
(2, 3, 'lame', 20121023120627)
(3, 1, 'useful', 20121023120627)
(3, 3, 'lame', 20121023120627)
(3, 4, 'useful', 20121023120627)
(4, 4, 'useful', 20121024120627)

但我需要的结果是，在desc order.if 2结果具有相同数字时显示从max到min的计数，那么最高结果将基于最新的date_created类似这样

POST_ID

     3
     2
     4

我当前的查询是

SELECT post_id
FROM tableName
GROUP BY post_ID
HAVING COUNT(*) = 
(
    SELECT MAX(x.counts)
    FROM
    (
        SELECT post_id, COUNT(*) counts
        FROM tableName
        GROUP BY post_id
    ) x
)

可以在SQLFiddle SQLFiddle

上找到该示例

Answer 1

但我需要的结果是，在desc上显示从max到min的计数 order.if 2结果具有相同的数字，那么最高的结果将是基于最新的date_created。

您需要ORDER BY COUNT(*) DESC, date_created DESC这样：

SELECT post_id
FROM tableName
GROUP BY post_ID
HAVING COUNT(*) = 
(
    SELECT MAX(x.counts)
    FROM
    (
        SELECT post_id, COUNT(*) counts
        FROM tableName
        GROUP BY post_id
    ) x
)
ORDER BY COUNT(*) DESC, date_created DESC

更新1

试试这个，

SELECT post_id
FROM tableName
GROUP BY post_ID
ORDER BY  COUNT(*) DESC, MAX(`date_created`) DESC

Mysql组post_id按最大计数状态

1 个答案:

Updated SQL Fiddle Demo