是否可以将浮动从大端转换为小端?我有一个来自大端程序平台的值,我通过UDP发送到Windows进程(little endian)。这个值是一个浮点数,但是当我尝试BitConverter.ToSingle时,我总是得到5.832204E-42,但它应该是36.000。
我做错了什么?
这是一段剪辑代码:
// Receive thread
private void ReceiveData()
{
int count = 0;
IPEndPoint remoteIP = new IPEndPoint(IPAddress.Parse("10.0.2.213"), port);
client = new UdpClient(remoteIP);
while (true)
{
try
{
IPEndPoint anyIP = new IPEndPoint(IPAddress.Any, 0);
byte[] data = client.Receive(ref anyIP);
float x = BitConverter.ToSingle(data, 0);
float y = BitConverter.ToSingle(data, 4);
float z = BitConverter.ToSingle(data, 8);
float alpha = BitConverter.ToSingle (data, 12);
float theta = BitConverter.ToSingle (data, 16);
float phi = BitConverter.ToSingle (data, 20);
print(">> " + x.ToString() + ", "+ y.ToString() + ", "+ z.ToString() + ", " +
alpha.ToString() + ", "+ theta.ToString() + ", "+ phi.ToString());
// Latest UDP packet
lastReceivedUDPPacket=x.ToString()+" Packet#: "+count.ToString();
count = count+1;
}
答案 0 :(得分:5)
36.0和5.832204E-42是endian-obposites,因此这是一个字节序问题。在Windows / .NET上,你通常是little-endian,所以我猜测数据是big-endian。这意味着您需要分别为每个值反转 (而不是整个数组)。
要以CPU安全的方式编写,最好选择BitConverter.IsLittleEndian
,并在必要时进行补偿。例如:
public static float ReadSingleBigEndian(byte[] data, int offset)
{
return ReadSingle(data, offset, false);
}
public static float ReadSingleLittleEndian(byte[] data, int offset)
{
return ReadSingle(data, offset, true);
}
private static float ReadSingle(byte[] data, int offset, bool littleEndian)
{
if (BitConverter.IsLittleEndian != littleEndian)
{ // other-endian; reverse this portion of the data (4 bytes)
byte tmp = data[offset];
data[offset] = data[offset + 3];
data[offset + 3] = tmp;
tmp = data[offset + 1];
data[offset + 1] = data[offset + 2];
data[offset + 2] = tmp;
}
return BitConverter.ToSingle(data, offset);
}
使用:
float x= ReadSingleBigEndian(data, 0);
float y= ReadSingleBigEndian(data, 4);
float z= ReadSingleBigEndian(data, 8);
float alpha= ReadSingleBigEndian(data, 12);
float theta= ReadSingleBigEndian(data, 16);
float phi= ReadSingleBigEndian(data, 20);