MySQL：基于行之前的查询顺序

Question

我有这样的数据库结构：

•Insured表

+-----------+--------------+-----+
| InsuredID |         Name | ... |
+-----------+--------------+-----+
|         1 |     John Doe | ... |
|         2 |   Bill Gates | ... |
|         3 |   Steve Jobs | ... |
+-----------+--------------+-----+

•Accompany表

+-------------+-----------+---------------+-----+
| AccompanyID | InsuredID |          Name | ... |
+-------------+-----------+---------------+-----+
|           1 |         1 |    Joanna Doe | ... |
|           2 |         1 |    Johnny Doe | ... |
|           3 |         3 | Steve Ballmer | ... |
+-------------+-----------+---------------+-----+

我怎样才能得到这个结果：

+----------------+-----+
|           Name | ... |
+----------------+-----+
|       John Doe | ... |
|     Joanna Doe | ... |
|     Johnny Doe | ... |
|     Bill Gates | ... |
|     Steve Jobs | ... |
|  Steve Ballmer | ... |
+----------------+-----+

如何将查询的顺序设为 - Insured然后Accompany，其中Accompany.InsuredID等同于Insured.InsuredID Accompany之前的InsuredID = 1 }。它应该这样订购：

1. John Doe（被保险人）InsuredID = 1
2. Joanna Doe（陪伴）InsuredID = 1
3. Johnny Doe（陪伴）InsuredID = 2
4. 比尔盖茨（被保险人）InsuredID = 3
5. 史蒂夫乔布斯（被保险人）InsuredID = 3
6. Steve Balmer（陪伴）{{1}}

Answer 1

这样的事情应该有效：

select name
from (
 select insuredid, name, 0 ins
 from insured
 union all
 select insuredid, name, 1 ins
 from  accompany) isq
order by insuredid, ins

基本上插入一个假列来标识这些行来自哪个表，然后按insuredid排序，然后按我们的任意表编号排序。

Answer 2

SELECT 
    * 
FROM (SELECT NAme,.... FROM Insured
      UNION ALL
      SELECT Name,.... FROM Accompany)
ORDER BY Name

Answer 3

未经测试，类似这样：

SELECT Name 
FROM (
      SELECT InsuredID, Name FROM Insured 
      UNION 
      SELECT InsuredID, Name FROM Accompany
     ) AS t
ORDER BY InsuredID