我的应用程序可以根据设置动态加载dll 来自数据库(文件,类和方法名称)。为了方便,加快和减少反射的使用,我希望有一个缓存....
遵循使用:
的想法 MethodInfo.Invoke
没有表现力(Reflection Performance - Create Delegate (Properties C#)) 我想翻译任何方法的调用。我想到了一些像这样的东西:
public static T Create<T>(Type type, string methodName) // or
public static T Create<T>(MethodInfo info) // to use like this:
var action = Create<Action<object>>(typeof(Foo), "AnySetValue");
一个要求是所有参数都可以是对象。
我正在尝试处理表达式,到目前为止,我有类似的东西:
private void Sample()
{
var assembly = Assembly.GetAssembly(typeof(Foo));
Type customType = assembly.GetType("Foo");
var actionMethodInfo = customType.GetMethod("AnyMethod");
var funcMethodInfo = customType.GetMethod("AnyGetString");
var otherActionMethod = customType.GetMethod("AnySetValue");
var otherFuncMethodInfo = customType.GetMethod("OtherGetString");
var foo = Activator.CreateInstance(customType);
var actionAccessor = (Action<object>)BuildSimpleAction(actionMethodInfo);
actionAccessor(foo);
var otherAction = (Action<object, object>)BuildOtherAction(otherActionMethod);
otherAction(foo, string.Empty);
var otherFuncAccessor = (Func<object, object>)BuildFuncAccessor(funcMethodInfo);
otherFuncAccessor(foo);
var funcAccessor = (Func<object,object,object>)BuildOtherFuncAccessor(otherFuncMethodInfo);
funcAccessor(foo, string.Empty);
}
static Action<object> BuildSimpleAction(MethodInfo method)
{
var obj = Expression.Parameter(typeof(object), "o");
Expression<Action<object>> expr =
Expression.Lambda<Action<object>>(
Expression.Call(
Expression.Convert(obj, method.DeclaringType),
method), obj);
return expr.Compile();
}
static Func<object, object> BuildFuncAccessor(MethodInfo method)
{
var obj = Expression.Parameter(typeof(object), "o");
Expression<Func<object, object>> expr =
Expression.Lambda<Func<object, object>>(
Expression.Convert(
Expression.Call(
Expression.Convert(obj, method.DeclaringType),
method),
typeof(object)),
obj);
return expr.Compile();
}
static Func<object, object, object> BuildOtherFuncAccessor(MethodInfo method)
{
var obj = Expression.Parameter(typeof(object), "o");
var value = Expression.Parameter(typeof(object));
Expression<Func<object, object, object>> expr =
Expression.Lambda<Func<object, object, object>>(
Expression.Call(
Expression.Convert(obj, method.DeclaringType),
method,
Expression.Convert(value, method.GetParameters()[0].ParameterType)),
obj, value);
return expr.Compile();
}
static Action<object, object> BuildOtherAction(MethodInfo method)
{
var obj = Expression.Parameter(typeof(object), "o");
var value = Expression.Parameter(typeof(object));
Expression<Action<object, object>> expr =
Expression.Lambda<Action<object, object>>(
Expression.Call(
Expression.Convert(obj, method.DeclaringType),
method,
Expression.Convert(value, method.GetParameters()[0].ParameterType)),
obj,
value);
return expr.Compile();
}
public class Foo
{
public void AnyMethod() {}
public void AnySetValue(string value) {}
public string AnyGetString()
{ return string.Empty; }
public string OtherGetString(string value)
{ return string.Empty; }
}
有没有办法简化这段代码? (我相信有可能只使用泛型创建一个方法..)当你有3,4,5个任何参数时,我会这样做吗?
我在想,如果有这样的事情会怎么样:
但是我会有更多的参数(在行动或功能中),这个参数(第一个参数)是一个要执行的对象。 这可能吗?
答案 0 :(得分:13)
我制作了一个满足您所有要求的示例程序(我想!)
class Program
{
class MyType
{
public MyType(int i) { this.Value = i; }
public void SetValue(int i) { this.Value = i; }
public void SetSumValue(int a, int b) { this.Value = a + b; }
public int Value { get; set; }
}
public static void Main()
{
Type type = typeof(MyType);
var mi = type.GetMethod("SetValue");
var obj1 = new MyType(1);
var obj2 = new MyType(2);
var action = DelegateBuilder.BuildDelegate<Action<object, int>>(mi);
action(obj1, 3);
action(obj2, 4);
Console.WriteLine(obj1.Value);
Console.WriteLine(obj2.Value);
// Sample passing a default value for the 2nd param of SetSumValue.
var mi2 = type.GetMethod("SetSumValue");
var action2 = DelegateBuilder.BuildDelegate<Action<object, int>>(mi2, 10);
action2(obj1, 3);
action2(obj2, 4);
Console.WriteLine(obj1.Value);
Console.WriteLine(obj2.Value);
// Sample without passing a default value for the 2nd param of SetSumValue.
// It will just use the default int value that is 0.
var action3 = DelegateBuilder.BuildDelegate<Action<object, int>>(mi2);
action3(obj1, 3);
action3(obj2, 4);
Console.WriteLine(obj1.Value);
Console.WriteLine(obj2.Value);
}
}
DelegateBuilder类:
public class DelegateBuilder
{
public static T BuildDelegate<T>(MethodInfo method, params object[] missingParamValues)
{
var queueMissingParams = new Queue<object>(missingParamValues);
var dgtMi = typeof(T).GetMethod("Invoke");
var dgtRet = dgtMi.ReturnType;
var dgtParams = dgtMi.GetParameters();
var paramsOfDelegate = dgtParams
.Select(tp => Expression.Parameter(tp.ParameterType, tp.Name))
.ToArray();
var methodParams = method.GetParameters();
if (method.IsStatic)
{
var paramsToPass = methodParams
.Select((p, i) => CreateParam(paramsOfDelegate, i, p, queueMissingParams))
.ToArray();
var expr = Expression.Lambda<T>(
Expression.Call(method, paramsToPass),
paramsOfDelegate);
return expr.Compile();
}
else
{
var paramThis = Expression.Convert(paramsOfDelegate[0], method.DeclaringType);
var paramsToPass = methodParams
.Select((p, i) => CreateParam(paramsOfDelegate, i + 1, p, queueMissingParams))
.ToArray();
var expr = Expression.Lambda<T>(
Expression.Call(paramThis, method, paramsToPass),
paramsOfDelegate);
return expr.Compile();
}
}
private static Expression CreateParam(ParameterExpression[] paramsOfDelegate, int i, ParameterInfo callParamType, Queue<object> queueMissingParams)
{
if (i < paramsOfDelegate.Length)
return Expression.Convert(paramsOfDelegate[i], callParamType.ParameterType);
if (queueMissingParams.Count > 0)
return Expression.Constant(queueMissingParams.Dequeue());
if (callParamType.ParameterType.IsValueType)
return Expression.Constant(Activator.CreateInstance(callParamType.ParameterType));
return Expression.Constant(null);
}
}
核心是 BuildDelegate 方法:
static T BuildDelegate<T>(MethodInfo method)
示例电话:var action = BuildDelegate<Action<object, int>>(mi);
参数规则:
如果传递的方法是实例方法,则生成的委托的第一个参数将接受包含方法本身的对象的实例。所有其他参数都将传递给方法。
如果传递的方法是静态方法,则生成的委托的所有参数都将传递给方法。
缺少参数将传递默认值。
答案 1 :(得分:3)
Delegate.CreateDelegate
比构建表达式树要简单得多。
var assembly = Assembly.GetAssembly(typeof(Foo));
Type customType = assembly.GetType("Foo");
var actionMethodInfo = customType.GetMethod("AnyMethod");
var foo = Activator.CreateInstance(customType);
Action action = (Action)Delegate.CreateDelegate(typeof(Action), foo, actionMethodInfo);
答案 2 :(得分:2)
我遇到了一个非常类似的场景,我发现以下内容非常适合。
首先,让我们设置我们的测试Foo类:
public class Foo
{
private string _name;
public Foo(string name)
{
_name = name;
}
public void AnyMethod()
{
Console.WriteLine("{0} Called: AnyMethod()", _name);
}
public void AnySetValue(string value)
{
Console.WriteLine("{0} Called: AnySetValue(string) with {1}", _name, value);
}
public string AnySetString(string value)
{
Console.WriteLine("{0} Called: AnySetString(string) with {1}", _name, value);
return value;
}
}
接下来,我们创建一组方法来创建可重用的方法包装器:
public static Action<object> CreateReusableAction<TClass>(string methodName)
{
var method = typeof(TClass).GetMethod(methodName);
var del = Delegate.CreateDelegate(typeof(Action<TClass>), method);
Action<object> caller = (instance) => del.DynamicInvoke(instance);
return caller;
}
public static Action<object, object> CreateReusableAction<TClass, TParam1>(string methodName)
{
var method = typeof(TClass).GetMethod(methodName, new Type[] { typeof(TParam1) });
var del = Delegate.CreateDelegate(typeof(Action<TClass, TParam1>), method);
Action<object, object> caller = (instance, param) => del.DynamicInvoke(instance, param);
return caller;
}
public static Func<object, object, object> CreateReusableFunction<TClass, TParam1, TReturn>(string methodName)
{
var method = typeof(TClass).GetMethod(methodName, new Type[] { typeof(TParam1) });
var del = Delegate.CreateDelegate(typeof(Func<TClass, TParam1, TReturn>), method);
Func<object, object, object> caller = (instance, param) => (TReturn)del.DynamicInvoke(instance, param);
return caller;
}
然后我们可以按如下方式使用它:
var myFoo = new Foo("myFoo");
var otherFoo = new Foo("otherFoo");
var anyMethod = CreateReusableAction<Foo>("AnyMethod");
anyMethod(myFoo);
anyMethod(otherFoo);
var anySetValue = CreateReusableAction<Foo, string>("AnySetValue");
anySetValue(myFoo, "Value 1");
anySetValue(otherFoo, "Value 2");
var anySetString = CreateReusableFunction<Foo, string, string>("AnySetString");
var firstResult = anySetString(myFoo, "MyFooValue1");
var secondResult = anySetString(otherFoo, "OtherFooValue1");
产生输出:
myFoo Called: AnyMethod()
otherFoo Called: AnyMethod()
myFoo Called: AnySetValue(string) with Value 1
otherFoo Called: AnySetValue(string) with Value 2
myFoo Called: AnySetString(string) with MyFooValue1
otherFoo Called: AnySetString(string) with OtherFooValue1
答案 3 :(得分:2)
如果您可以在项目中使用库,请尝试使用Impromptu接口(可在此处获取:http://code.google.com/p/impromptu-interface/)或nuget。
它具有许多用于处理类型反射的功能,还实现了内部缓存。我一直在一个严重依赖反射的项目中使用它,性能非常好。
库本身具有很多功能,但它也可以处理像你这样的场景。
答案 4 :(得分:0)
我不确定,但为什么你不使用dynamic
类型?
例如:
dynamic foo = Activator.CreateInstance(customType);
foo.AnyMethod();
foo.AnySetValue("test string");
foo.OtherMethod("method", "with", "many", "parameters");
答案 5 :(得分:0)
我有点不确定你真正想做什么,但也许这有帮助吗?
public static Func<object, object[], object> CreateDelegate(MethodInfo method)
{
return new Func<object, object[], object>((object instance, object[] args) => method.Invoke(instance, args));
}
// Merely providing syntactic suger, ie able to write
// method.MyInvoke(instance, arg1, arg2, arg3, arg4)
// instead of having to put the args in an array, ie Invoke(instance, new object[]{arg1, arg2}) etc
public static object MyInvoke(this Func<object, object[], object> func, object instance, params object[] args)
{
return func(instance, args);
}
public static void TestCode()
{
var method = typeof(string).GetMethod("get_Length");
var wrappfunc = CreateDelegate(method);
// Calling get_Length (ie Length property) on the string "klasjf"
wrappfunc.MyInvoke("klasjf");
}
你会失去强类型,因为所有的参数都是object
,我有点不确定你真正要完成的是什么。