Question

我执行模块popen1.py并使用子进程模块

调用popen2.py

但popen2.py的输出没有显示..当我显示子进程ID时，它正在显示..输出将打印为popen2.py

呼叫

child = subprocess.Popen(['python', 'popen2.py',"parm1='test'","parm='test1'"], shell=True,
                        stdin=subprocess.PIPE,
                         stdout=subprocess.PIPE, stderr=subprocess.PIPE)

Answer 1

完成此过程后，您可以阅读child.stdout和child.stderr来获取数据（因为您通过了subprocess.PIPE）

或者，您可以使用oudata,errdata = child.communicate()等待子流程完成，然后将其输出为字符串。

从设计角度来看，最好导入。我会按如下方式重构popen2.py：

#popen2.py
# ... stuff here
def run(*argv):
    #...

if __name__ == '__main__':
    import sys
    run(sys.argv[1:])

然后你可以在popen1.py中导入并运行popen2.py：

#popen1.py
import popen2
popen2.run("parm1=test","parm=test1")

Answer 2

您可以使用child.stdout / child.stdin与进程通信：

child = subprocess.Popen(['python', 'popen2.py',"parm1='test'","parm='test1'"], shell=True,
                    stdin=subprocess.PIPE,
                     stdout=subprocess.PIPE, stderr=subprocess.PIPE)
print child.stdout.readlines()

通过Popen执行模块

2 个答案: