Question

我有一个以下列格式返回数据的查询：

id | name | number
 1   John    12545
 1   John    50496
 2   Mary    23443
 3   Mark    54
 3   Mark    5600
 3   Mark    50206

我想找出结果集中出现的不同ids的数量。例如，对于上面的结果。我想获得值3。

有没有办法添加一列，所以结果看起来像这样呢？

count | id | name | number
 3      1   John    12545
 3      1   John    50496
 3      2   Mary    23443
 3      3   Mark    54
 3      3   Mark    5600
 3      3   Mark    50206

我的查询是：

 SELECT * FROM (
    SELECT id FROM tableA
    WHERE xyz
 ) as t1
 JOIN tableB using (id)

Answer 1

SELECT (SELECT COUNT(DISTINCT id) FROM tableName) totalCount,
       id,name,number
FROM tableName

或使用CROSS JOIN

SELECT x.totalCount,
       a.id, a.name, a.number
FROM tableName a, (SELECT COUNT(DISTINCT id) totalCount 
                   FROM tableName) x

Answer 2

你应该尝试：

SELECT id,name,number, (SELECT COUNT(DISTINCT name) FROM YourTableName) FROM YourTableName

祝你好运

Answer 3

SELECT COUNT(DISTINCT id)比使用列name更快。

SELECT (SELECT COUNT(DISTINCT id) FROM tableName) as 'count',
        id,name,number  
FROM tableName

Answer 4

SELECT COUNT(id) AS count , id, name, number 
FROM 
( 
    SELECT id 
    FROM tableA 
    WHERE xyz 
) as t1 
JOIN tableB using (id)
GROUP BY id, name, number

计算MySQL列中的唯一数字

4 个答案: