我正在处理一个有多个数据库调用的perl脚本,并且我不断收到以下错误:
DB-Library错误: 尝试启动具有待处理结果的新SQL Server操作。
在我的代码中,我有以下内容:
对数据库的第一次调用执行了许多根据哈希构建的插入语句:
while (my ($key, $value) = each(%holidays)) {
system("log4k", "DEBUG", "$0", "Staging holiday info data for: $cal_name: $key");
$sql = "INSERT INTO stg_holiday_data (hol_mnemonic, hol_date, hol_comment, dml_type) VALUES (\"$cal_name\", $key, \"$value\", \"N\")";
system("log4k", "TRACE", "$0", "SQL being executed: $sql");
if ($test == 0) {
$dbh->dbcmd($sql);
($dbh->dbsqlexec() && $dbh->dbresults)
or &fatalError("Database error in $sql", "DB_ERROR");
while($dbh->dbresults != NO_MORE_RESULTS) {
while(my @dat = $dbh->dbnextrow){}
}
}
}
在完成后立即关闭连接,取消连接以确保没有结果可以通过发出来处理:
$dbh->dbcancel();
$dbh->dbclose();
从那里我调用一个单独的子程序来执行一个存储过程,它将产生三行输出,表示行号:
子程序调用
&run_sproc() if ($test == 0);
子程序:
sub run_sproc() {
system("log4k", "DEBUG", "$0", "Loading staged holiday data");
my $sql1 = "upd_holiday_data";
system("log4k", "TRACE", "$0", "SQL being executed: $sql1");
my($dbh2) = new Sybase::DBlib $ENV{DATABASE_USER}, $ENV{DATABASE_PASSWORD}, $ENV{DATABASE_SERVER}, "GME_calendar_sync";
&fatalError("Failed to login imagine database", "DB_LOGIN_ERROR") unless ($dbh2);
$dbh2->dbcmd($sql1);
($dbh2->dbsqlexec() && $dbh2->dbresults )
or &fatalError ("Database error in $sql", "DB_ERROR");
while ($dbh2->dbresults != NO_MORE_RESULTS) {
while (my @d = $dbh2->dbnextrow) {
system("log4k", "TRACE", "$0", "Next row being inserted @d");
}
}
$dbh2->dbclose();
}
我确实有一个第三个SQL块,它存储在没有这个子例程的存储过程之后。
发生的事情是我在存储过程打印结果之前收到上述错误。我已经尝试了所有我能想象的东西,以确保所有结果都得到处理。日志输出的示例如下:
[Tuesday, 23 October 2012 13:30:02 BST] [DEBUG] gme_process_calendars.pl: Staging holiday info data for: CA: 20251226
[Tuesday, 23 October 2012 13:30:03 BST] [TRACE] gme_process_calendars.pl: SQL being executed: INSERT INTO stg_holiday_data (hol_mnemonic, hol_date, hol_comment, dml_type) VALUES ("CA", 20251226, "upload", "N")
[Tuesday, 23 October 2012 13:30:03 BST] [DEBUG] gme_process_calendars.pl: Staging holiday info data for: CA: 20220103
[Tuesday, 23 October 2012 13:30:03 BST] [TRACE] gme_process_calendars.pl: SQL being executed: INSERT INTO stg_holiday_data (hol_mnemonic, hol_date, hol_comment, dml_type) VALUES ("CA", 20220103, "upload", "N")
[Tuesday, 23 October 2012 13:30:03 BST] [DEBUG] gme_process_calendars.pl: Loading staged holiday data
[Tuesday, 23 October 2012 13:30:03 BST] [TRACE] gme_process_calendars.pl: SQL being executed: upd_holiday_data
DB-Library error:
Attempt to initiate a new SQL Server operation with results pending.
[Tuesday, 23 October 2012 13:30:03 BST] [TRACE] gme_process_calendars.pl: Next row being inserted 310107230
任何有关此方面的帮助都将非常感激,因为我已经尝试了一些我可以在互联网上搜索和阅读文档的内容。
谢谢
答案 0 :(得分:0)
我认为您的问题是您的run_proc
方法尝试执行此SQL:
my $sql1 = "upd_holiday_data";
我怀疑它是一个有效的SQL命令
答案 1 :(得分:0)
在run_sproc子例程中,检查:
($dbh2->dbsqlexec() && $dbh2->dbresults )
or &fatalError ("Database error in $sql", "DB_ERROR");
第二个条件$ dbh2-> dbresults是导致此错误情况的原因,一旦删除该错误就不再出现了。