import java.applet.Applet;
import java.awt.*;
import java.awt.event.*;
import java.net.*;
import java.io.*;
public class RegisterUser extends Applet{
TextField panel1 = new TextField(10);
TextField panel2 = new TextField(10);
TextField panel3 = new TextField(10);
Button save = new Button("Save");
public void init(){
add(panel1);
add(new Label("Name:"));
addNewLine();
add(panel2);
add(new Label("Last:"));
addNewLine();
add(save);
addNewLine();
save.addActionListener(new SaveListener());
}
class SaveListener implements ActionListener{
public void actionPerformed(ActionEvent event){
URL myURL = new URL("http://myplace/2272/save.php");
URLConnection myURLConnection = myURL.openConnection();
myURLConnection.connect();
}
}
private void addHorizontalLine(Color c)
{
Canvas line = new Canvas( );
line.setSize(10000,1);
line.setBackground(c);
add(line);
}
private void addNewLine( )
{
addHorizontalLine(getBackground( ));
}
}
上面的代码是一个java applet。这是名字姓氏电子邮件enterence的GUI。它有一个按钮。我想在单击按钮时调用php脚本-save.php-。我在我的actionPerformed方法中尝试了它,但它不起作用。
我该怎么做。
这是我下面的php脚本
<?php
session_start();
$fp = fopen('users.txt', 'a+');
fwrite($fp, "\nname: " . $_GET["name"] . "\n");
fwrite($fp, "last name: " . $_GET["last_name"] . "\n");
fwrite($fp, "email: " . $_GET["email"] . "\n");
fclose($fp);
$_SESSION['registered']=1;
header( 'Location: http://myplace2272/save.php' ) ;
?>
我不确定脚本是否正确?
applet在没有php脚本调用的情况下正常工作。
答案 0 :(得分:3)
当您调用save.php时,您需要使用它传递参数:
URL myURL = new URL("http://myplace/2272/save.php?name="+panel1.getText()+"&last_name="+panel2.getText()+"&email="+panel3.getText());