我在codeigniter中设置此功能以作为cron作业运行,并在X时刻记录所有用户。我在选择一个用户并将该用户注销时成功使用了此代码,但是在添加foreach时,我收到以下错误:
Error Number: 1062
Duplicate entry '3858' for key 'PRIMARY'
INSERT INTO `time` (`id`, `projectid`, `phaseid`, `firstname`, `timest`, `status`, `activityid`, `todate`, `remark`, `time`, `workperiod`, `activitydate`, `entrydate`) VALUES ('3858', '212132 Unilever Nigeria  10000L Toothpaste Storage Tanks x 2', '1', 'BONGANI', '1347610976', '1', '1', '1', '1', 3335907, 'nothing', '2012-09-14 10:22:56', '2012-10-23 01:01:23')
Filename: C:\xampp\htdocs\projectfiles\protime\v2\system\database\DB_driver.php
Line Number: 330
这是该模型的代码:
function punch_out() {
$this -> load -> database();
$this -> load -> helper('date');
//get people
$this -> db -> select('*');
$this -> db -> from('person');
$this -> db -> order_by("department", "asc");
$this -> db -> order_by("userid", "asc");
$query = $this -> db -> get();
foreach ($query->result_array() as $row) {
$people[] = $row;
}
foreach ($people as $row) :
$this -> db -> from('punch');
$this -> db -> where('firstname', $row['firstname']);
$this -> db -> order_by("id", "desc");
$this -> db -> limit(1);
$query = $this -> db -> get();
foreach ($query->result_array() as $row) {
$data = $row;
}
$data['workperiod'] = 'nothing';
$current_time = getdate();
if ($current_time['wday'] > '0' && $current_time['wday'] < '5') {
if ($current_time['hours'] > '7' && $current_time['hours'] < '12') {
$data['workperiod'] = 'stda';
} else if ($current_time['0'] > strtotime('4:16am') && $current_time < strtotime('11:59pm')) {
$data['workperiod'] = 'ota';
}
} else if ($current_time['wday'] == '5') {
if ($current_time['0'] > strtotime('7:00am') && $current_time < strtotime('11:59am')) {
$data['workperiod'] = 'stdb';
} else if ($current_time['0'] > strtotime('1:01am') && $current_time < strtotime('11:59pm')) {
$data['workperiod'] = 'otb';
}
} else if ($current_time['wday'] == '6') {
$data['workperiod'] = 'otc';
} else if ($current_time['wday'] == '0') {
$data['workperiod'] = 'dtc';
}
if ($data['status'] == 1) {
//MAKE TIME
$now = time();
$data['time'] = elapsed_time($data['timest'], $now);
$data['entrydate'] = timestamp_to_mysqldatetime($now);
$data['activitydate'] = timestamp_to_mysqldatetime($data['timest']);
$this -> db -> insert('time', $data);
}
endforeach;
}
答案 0 :(得分:1)
如果您正在尝试更新要插入的相同ID的数据(time,entrydate,activitydate),我认为如果只将数据放入新数组中会更好:
if ($data['status'] == 1) {
//MAKE TIME
$now = time();
$newdata['time'] = elapsed_time($data['timest'], $now);
$newdata['entrydate'] = timestamp_to_mysqldatetime($now);
$newdata['activitydate'] = timestamp_to_mysqldatetime($data['timest']);
$this -> db -> where('id',$data['id']);
$this -> db -> update('time', $newdata);
}
或者,如果您尝试将新记录插入数据库,只需更改您要插入的阵列名称:
if ($data['status'] == 1) {
//MAKE TIME
$now = time();
$newdata['time'] = elapsed_time($data['timest'], $now);
$newdata['entrydate'] = timestamp_to_mysqldatetime($now);
$newdata['activitydate'] = timestamp_to_mysqldatetime($data['timest']);
$this -> db -> insert('time', $newdata);
}
通过这种编码方式,这可能会避免将来出现更多错误,并可能节省时间。
干杯!
答案 1 :(得分:0)
如果我正确阅读此内容,$data
包含有关每个“打卡”的详细信息,包括$data['id']
,该打卡的唯一ID。由于您从未从$data['id']
中删除$data
字段,因此当您使用time
作为源插入$data
数据库中的条目时,您还要指定新条目与你所汲取的冲击力具有相同的id
。尝试运行两次后,您将插入两行id
,并且您的错误似乎表明id
表上的time
字段设置为PRIMARY - 这意味着它不能有任何重复。
我认为,如果我正确理解您的代码和数据结构,那么在运行插入之前解决方案是unset($data['id'])
。