Question

我希望有人可以帮助我。下面的代码来自WordPress插件。从插件选项页面我输入一些简单的html -

<h3>Showname</h3><p>with DJ Top</p>

使用下面的代码（$ showname）来显示我输入的内容，但它实际上显示HTML而不是处理它，即显示HTML标题和段落。

任何人都可以指出我的方向，所以$ showname处理HTML而不是只打印出逐字标签和所有。

非常感谢

罗布

function showtime_schedule_handler($atts, $content=null, $code=""){

global $wpdb;
global $showtimeTable;

//Get the current schedule, divided into days
$daysOfTheWeek = array("Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday");

$schedule = array();

$output = '';

foreach ($daysOfTheWeek as $day) {
    //Add this day's shows HTML to the $output array
    $showsForThisDay =  $wpdb->get_results( $wpdb->prepare ( "SELECT * FROM $showtimeTable WHERE dayOfTheWeek = '$day' ORDER BY startTime" ));

    //Check to make sure this day has shows before saving the header
    if ($showsForThisDay){
        $output .= '<h2>'.$day.'</h2>';
        $output .= '<ul class="showtime-schedule">';
        foreach ($showsForThisDay as $show){
            $showName = $show->showName;
            $startClock = $show->startClock;
            $endClock = $show->endClock;
            $linkURL = $show->linkURL;

            if ($linkURL){
                $showName = '<a href="'.$linkURL.'">'.$showName.'</a>';
            }
            $output .= '<li><strong>'.$startClock.'</strong> - <strong>'.$endClock.'</strong>: '.$showName.'</li>';

        }
        $output .= '</ul>';
    }
}
return $output;
}

Answer 1

您输出的是text/plain MIME类型的变体。您需要使用默认标头（text/html）将其发送出去，以便浏览器正确解析它。

例如：

<?php
    header('Content-Type: text/html', true);
    echo showtime_schedule_handler($atts, $content);
?>

Answer 2

而不是

return $output;

尝试

return html_entity_decode($output);

PHP打印出HTML而不是处理HTML

2 个答案: