我有一个带有默认值的参数的方法。我需要知道值是来自用户还是默认值。用户也可以发送默认值。我怎么知道价值来自哪里?
答案 0 :(得分:12)
你可以使用Nobu Nakada在2004年提出的技巧:
def some_method( a=(implicit_value=true; 1) )
puts "a=#{a}; was set #{ implicit_value ? :im : :ex }plicitly"
end
> some_method
a=1; was set implicitly
> some_method 1
a=1; was set explicitly
> some_method 2
a=2; was set explicitly
答案 1 :(得分:4)
这也会起作用,看起来不那么难看:
def my_method(a = implicit = 1)
p a
p implicit
end
# when calling without parameters then a = implicit = 1 is run, hence implicit is assigned a value
> my_method
1
1
# when calling with a parameter then a = 1 statement is run. implicit will become nil here
> my_method 1
1
nil