如何将参数从@ Url.Action传递给控制器​​函数

Question

我有一个功能CreatePerson(int id)，我想从id传递@Url.Action。

以下是参考代码：

public ActionResult CreatePerson(int id) //controller 
window.location.href = "@Url.Action("CreatePerson", "Person") + id";

上述代码无法将id值传递给CreatePerson函数。

Answer 1

你可以这样传递：

Url.Action("CreatePerson", "Person", new RouteValueDictionary(new { id = id }));

OR也可以通过这种方式

Url.Action("CreatePerson", "Person", new { id = id });

Answer 2

public ActionResult CreatePerson (string id)

window.location.href = '@Url.Action("CreatePerson", "Person" , new {id = "ID"})'.replace("ID",id);

public ActionResult CreatePerson (int id)

window.location.href = '@Url.Action("CreatePerson", "Person" , new {id = "ID"})'.replace("ID", parseInt(id));

Answer 3

public ActionResult CreatePerson(int id) //controller 

window.location.href = '@Url.Action("CreatePerson", "Person")?id=' + id;

或者

var id = 'some value';
window.location.href = '@Url.Action("CreatePerson", "Person", new {id = id})';

Answer 4

这种方法将值从Controller传递给View：

ViewData["ID"] = _obj.ID;

以下是将值从View传递回Controller的方法：

<input type="button" title="Next" value="Next Step" onclick="location.href='@Url.Action("CreatePerson", "Person", new { ID = ViewData["ID"] })'" />

Answer 5

尝试一下：

public ActionResult CreatePerson(int id) //controller 

window.location.href = "@Url.Action("CreatePerson", "Person")?Id='+Id+'";

它可以正常传递参数。

Answer 6

你应该以这种方式传递它：

public ActionResult CreatePerson(int id) //controller 
window.location.href = "@Url.Action("CreatePerson", "Person",new { @id = 1});

Answer 7

@Url.Action("Survey", "Applications", new { applicationid = @Model.ApplicationID }, protocol: Request.Url.Scheme)

Answer 8

如果您在JavaScript中使用Url.Action，那么您可以

var personId="someId";
$.ajax({
  type: 'POST',
  url: '@Url.Action("CreatePerson", "Person")',
  dataType: 'html',
  data: ({
  //insert your parameters to pass to controller
    id: personId 
  }),
  success: function() {
    alert("Successfully posted!");
  }
});

Answer 9

试试这个

public ActionResult CreatePerson(string Enc)

 window.location = '@Url.Action("CreatePerson", "Person", new { Enc = "id", actionType = "Disable" })'.replace("id", id).replace("&", "&");

你将在Enc字符串中获得id。

Answer 10

需要两个或多个参数将Throw视图传递给控制器​​使用此语法... 试试。。

var id=0,Num=254;var str='Sample';    
var Url = '@Url.Action("ViewNameAtController", "Controller", new RouteValueDictionary(new { id= "id", Num= "Num", Str= "str" }))'.replace("id", encodeURIComponent(id));
    Url = Url.replace("Num", encodeURIComponent(Num));
    Url = Url.replace("Str", encodeURIComponent(str));
    Url = Url.replace(/&/g, "&");
window.location.href = Url;