Question

我有以下课程

public class Booking
{
    public string Group { get; set; }
    public BookingType Type { get; set; }
    public BookingStatus Status { get; set; }
    public InvoiceFreq { get; set; }
    public InvoiceLevel { get; set; }
}

我需要按Linq中的所有属性对它们进行分组，以便最后两个属性在分组结果中形成一个新字段。像这样：

        Group   Type    Status      InvoiceType          
        -------------------------------------------
        Group1  Online  New         Daily-Single
        Group2  Phone   Accepted    Daily-Single
        Group3  Store   Accepted    Weekly-Single
        Group3  Store   Accepted    Weekly-Bulk

此处InvoiceFreq将为Daily / Weekly，InvoiceLevel = Single或Bulk。

我到目前为止的查询是：

        var query = from b in Bookings
                        group b by new
                        {
                            b.Group, 
                            b.Type, 
                            b.Status,
                            b.InvoicingFrequency,
                            b.InvoicingLevel
                        } into bookingGroup
                        select new BookingSummaryLine()
                        {
                            Group = bookingGroup.Key.UserGroup,
                            Type = bookingGroup.Key.UserGroup,
                            Status = bookingGroup.Key.FinancialStatus,
                            InvType = String.Format({0}-{1},bookingGroup.Key.InvoicingFrequency, bookingGroup.Key.InvoicingLevel
                        };

这当然没有给出所需的结果，因为这两个属性分别是匿名类型。

有没有办法在Linq中实现这个目标？

Answer 1

这应该有效：

var query = from b in Bookings
    group b by new
    {
        b.Group, 
        b.Type, 
        b.Status,
        InvType = String.Format({0}-{1},b.InvoicingFrequency, b.InvoicingLevel)
    } into bookingGroup
    select new BookingSummaryLine()
    {
        Group = bookingGroup.Key.UserGroup,
        Type = bookingGroup.Key.UserGroup,
        Status = bookingGroup.Key.FinancialStatus,
        InvType = bookingGroup.Key.InvType
    };

Answer 2

我对linq的语法不太确定，但对于lambda，我会使用它。如果您尝试对所有列进行分组，则基本上使用distinct。

Context.Booking.Distinct().Select(z=> new BookingSummaryLine { Group = z.Group, Type =        z.Type, Status = z.Status, InvType = (z.InvoiceFrequency + "-" + z.InvoiceLevel });

在Linq中由两个属性组成一个

2 个答案: