Question

在2010 Visual C ++ Express中，我正在使用 ...

ifstream inFile("inputfile.dat");
double number;
while(inFile >> number)
{
cout << number << endl;
}

...将存储在文件中的8个数字读入程序，并在监视器上显示。它会根据需要正确显示它们，但我需要将每个单独的数字存储为已指定的双精度数。从上到下，

客户1的身份证明
余额
未付款
已经购买

那么其他4个数字对于不同的客户来说都是一样的。我尝试了很多不同的方法，但每个方法都有：

"Run-Time Check Failure #3 - The variable 'variableName' is 
 being used without being initialized."

几乎所有变量都会发生这种情况。我已经搜索了任何可以帮助我的东西，但似乎找不到能帮助我达到我需要的程度的东西。

Answer 1

假设您确实希望将这些存储在8个不同的变量中，而不是存储在某些聚合数据类型中：

std::ifstream inFile("inputfile.dat");
double number;

    if(inFile >> cust1id >> cust1bal >> cust1pay >> cust1purch >> 
                 cust2id >> cust2bal >> cust2pay >> cust2purch) {
      std::cout << 
        "Customer 1's Identification #: " << cust1id << "\n" <<
        "Balance: " < cust1bal << "\n" <<
        "Payments outstanding: " << cust1pay << "\n" <<
        "Purchases that have been made: " << cust1purch << 
        "Customer 2's Identification #: " << cust2id << "\n" <<
        "Balance: " < cust2bal << "\n" <<
        "Payments outstanding: " << cust2pay << "\n" <<
        "Purchases that have been made: " << cust2purch << "\n"; 
     }

文件流问题

1 个答案: