Question

我有两张桌子，结构相同

clients包含第1 + 2行
clients3仅限第2行

我想删除clients表

中的第2行

 SELECT * 
 FROM clients 
 WHERE EXISTS (SELECT * FROM clients3 WHERE clients3.id = clients.id))

给了我第2行。但我不知道如何删除。

DELETE * 
FROM clients 
WHERE (SELECT * 
       FROM clients 
       WHERE EXISTS (SELECT * FROM clients3 WHERE clients3.id = clients.id))

不起作用。

Answer 1

您需要为子查询创建临时表

DELETE 
FROM clients 
WHERE ID IN 
(
    SELECT ID
    FROM
    (
        SELECT ID FROM clients WHERE EXISTS (SELECT * FROM clients3 WHERE clients3.id = clients.id)
    ) x
)

Answer 2

无需在查询中两次引用clients表格，并从*子句中删除DELETE -

DELETE c1
FROM clients c1
INNER JOIN clients3 c3 ON c3.id = c1.id --INNER JOIN will work as EXISTS for 1-1 Relation

Answer 3

试试这个

   Delete from clients where id  in(select clients3.id from clients3)

sql删除查询结果

3 个答案: