只要该服务,线程是从android服务运行的吗?

时间:2012-10-20 11:32:08

标签: java android multithreading service kill

我从一个android服务启动一个线程,该服务不断地使用tcp连接将文件上传到服务器。该线程有一个执行此操作的while(true)循环。操作会在某个时间执行,但随后会停止。我尝试使用adb logcat进行调试,并查看我在线程中打印的某些消息只有一段时间。之后他们也停了下来。此外,当我停止服务时,我得到了一个N​​ullPointerException,因为在我使用线程对象的服务的onDestroy()方法中。

只要服务运行,线程是否会被杀死并且不会运行?我是否需要在服务类本身的onStart()中执行(true)操作而不生成新线程?

提供的任何解决方案都会有很大帮助。

代码如下:

    public void run() 
    {           
        Log.d("TAG","Starting Thread");         
        String data = "";   
        updateServer();
        while(flag)
        {                   
            String path = extStorageDirectory + "/" + appFolder + "/" + "SAT_pingLog_" + Long.toString(System.currentTimeMillis()) + ".txt";
            createFile(path);
            int count = 0;
            while(flag && count < 32768)
            {                               
                data = "";          
                String result = Long.toString(getLatency(url));                                     
                data = Long.toString(System.currentTimeMillis()) + " " + gps[0] + " " + gps[1] + " " + strength + " " + result;
                Log.d("DEBUGGING",data);
                writeToLog(path,data);
                try 
                {
                    Thread.sleep(sleepTime);
                } 
                catch (InterruptedException e) 
                {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
                count++;
            }
            updateServer();
        }           
    }public long getLatency(String Url)
    {
        long startTime = 0, endTime = 0, latency = 0;                   
        try 
        {
            HttpParams httpParameters = new BasicHttpParams();
            // Set the timeout in milliseconds until a connection is established.
            // The default value is zero, that means the timeout is not used. 
            int timeoutConnection = 10000;
            HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection);
            // Set the default socket timeout (SO_TIMEOUT) 
            // in milliseconds which is the timeout for waiting for data.
            int timeoutSocket = 10000;
            HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
            DefaultHttpClient httpclient = new DefaultHttpClient(httpParameters);
            HttpHead httphead = new HttpHead(Url);
            //HttpParams httpParameters = new BasicHttpParams();                
            //HttpConnectionParams.setConnectionTimeout(httpParameters, 5000);
            //HttpConnectionParams.setSoTimeout(httpParameters, 5000);
            //HttpClient httpClient = new DefaultHttpClient(httpParameters);
            //request.setURI(new URI("http://www.google.com"));
            System.out.println("Executing request " + httphead.getURI());
            Log.d("DEBUGGING","STARTING EXECUTE");
            startTime = System.currentTimeMillis();             
            HttpResponse response = httpclient.execute(httphead);
            endTime = System.currentTimeMillis();
            Log.d("DEBUGGING","ENDING EXECUTE");
            int status = response.getStatusLine().getStatusCode();
            if (status == HttpStatus.SC_OK)                                
                latency = endTime - startTime;                                      
            else
                latency = 0;
        } 
        catch(Exception e)
        {
            Log.d("DEBUGGING","EXCEPTION CAUGHT");
            e.printStackTrace();
        }   
        Log.d("DEBUGGING","LATENCY:"+Long.toString(latency));
        return latency;
    }       
}

1 个答案:

答案 0 :(得分:3)

  

只要服务运行,线程是否会被杀死并且不会运行?

Android组件无视他们未创建的线程。因此,虽然IntentService将处理它为onHandleIntent()使用而创建的线程,但是常规Service将不会关注您自己分叉的任何线程。

一旦服务被销毁,它泄漏的任何线程将继续运行,直到Android终止该过程为止。

如果您的线程意外停止,那与Service无关 - 再次,Service自己的线程一无所知。确保你没有通过空catch块来静默地吃异常,因为我的猜测是某些东西引发异常,导致你退出循环,但是你没有因某种原因记录它。 / p>