Question

因为你不能自动递增两列，查询将获得表的最后一行，列的+1值来插入新行。

例如，我有一个名为players

的表

看起来像这样：

id    player_id    player_name
 1      15           name1
 2      16           name2
 3      17           name3

我正在尝试创建一个管理面板来从表单创建一个播放器，列'id'自动递增但我也需要增加player_id，但是id和player_id彼此并不相同。

类似于此的查询（我做了这个，所以你可以更好地理解）

$sql="select top 1 * from `players`  order by id desc";
$result =mysql_query($sql);
while ($data=mysql_fetch_assoc($result)){
    $playerid=$data['player_id'];
    Insert into `players` (`player_id`,`player_name`) VALUE ('$playerid' + '1', 'name4');

}

Answer 1

试用此代码：

    $sql="SELECT player_id FROM `players` ORDER BY id DESC LIMIT 1";
    $result =mysql_query($sql);
    while ($data=mysql_fetch_assoc($result)){
        $playerid=$data['player_id']+1;
       }
mysql_query("Insert into `players` (`player_id`,`player_name`) VALUES ('".$playerid."','name4')");

Answer 2

以下查询将在插入时分配下一个可用的player_id。

INSERT INTO `players` (`player_id`, `player_name`)
SELECT MAX(`player_id`)+1, 'name4'
FROM `players`;

Answer 3

试试这种方式

  $sql="SELECT * FROM `players` ORDER BY id DESC LIMIT 1";
    $result =mysql_query($sql);
    $data=mysql_fetch_assoc($result);
    $playerid=$data['player_id']+1;

mysql_query("Insert into `players` (`player_id`,`player_name`) VALUES ('".$playerid."','name4')");

SQL查询从最后一行增加1？

3 个答案: