Question

正如我在标题中提到的，我正在'bid_userloc'表中请求纬度和经度......但我需要结合'wp_usermeta'表中的信息......

SET @centerLat = '48.531157';
SET @centerLng = '-123.782959';

SELECT *, ( 3959 * acos( cos( radians( @centerLat ) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(@centerLng) ) + sin( radians( @centerLat ) ) * sin( radians( lat ) ) ) ) AS distance FROM bid_userloc HAVING distance < 25 ORDER BY distance LIMIT 0 , 20

使用user_id中的SELECT *，我需要从wp_userdata表中获取一些如下所示的用户数据：

id
meta_key
meta_value

例如，我需要meta_value的{{1}}“昵称”......以及其他一些昵称，但是一旦我看到它是如何完成的，我可以添加更多。< / p>

我真的很感激！

Answer 1

试试这个，将距离替换为原来的距离，然后用真实的东西替换其他东西：

SET @centerLat = '48.531157';
SET @centerLng = '-123.782959';

SELECT bid_userloc.*, distance, nickname.meta_value, something_else.meta_value
FROM bid_userloc
LEFT JOIN wp_usermeta AS nickname 
    ON nickname.userid = bid_userloc.user_id 
        AND nickname.meta_key = 'nickname'
LEFT JOIN wp_usermeta AS something_else 
    ON something_else.userid = bid_userloc.user_id 
        AND something_else.meta_key = 'something_else'
HAVING distance < 25
ORDER BY distance 
LIMIT 0 , 20

Answer 2

修改后的答案如下：

SET @centerLat = '48.531157';
SET @centerLng = '-123.782959';

SELECT bid_userloc.*, nickname.meta_value, last_name.meta_value,
( 3959 * acos( cos( radians( @centerLat ) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(@centerLng) ) + sin( radians( @centerLat ) ) * sin( radians( lat ) ) ) ) AS distance
FROM bid_userloc
LEFT JOIN wp_usermeta AS nickname 
    ON nickname.user_id = bid_userloc.user_id 
        AND nickname.meta_key = 'nickname'
LEFT JOIN wp_usermeta AS last_name 
    ON last_name.user_id = bid_userloc.user_id 
        AND last_name.meta_key = 'last_name'
HAVING distance < 25
LIMIT 0 , 20

MySQL：搜索一个简单的表，但将WordPress的'wp_usermeta'表与meta_key / meta_value组合

2 个答案: