Question

我搜索过并发现了许多与我类似的问题，但没有一个解决方案适合我。这是在Oracle中，我不知道该版本（我只通过SQL Developer访问它）。我有两个表（省略了不相关的列）：

describe t_points_receipt
Name              Null     Type          
----------------- -------- ------------- 
USER_ID           NOT NULL NUMBER(9)     
PROMOTION_ID      NOT NULL NUMBER(9)     
AMOUNT            NOT NULL NUMBER(9,2)   

describe t_user_promotion_points
Name         Null     Type        
------------ -------- ----------- 
USER_ID      NOT NULL NUMBER(9)   
PROMOTION_ID NOT NULL NUMBER(9)   
TOTAL_POINTS          NUMBER(9,2)

而且，我有这个问题：

select user_id, promotion_id, sum(amount) from t_points_receipt
 where promotion_id = 10340 group by user_id, promotion_id;

我想要做的是从t_user_promotion_points.user_id =（results）.user_id和t_user_promotion_points.promotion_id =（results）.promotion_id的结果中用sum（amount）更新t_user_promotion_points。有没有办法做到这一点？

Answer 1

update t_user_promotion_points p
set total_points = select sum(amount) from t_points_receipt r
on p.user_id = r.user_id 
where r.promotion_id = 10340 and
where t.promotion_id = 10340

Answer 2

您可以为要设置的值创建相关子查询：

update t_user_promotion_points p
set total_points = (select sum(amount) from t_points_receipt r where p.user_id = r.user_id and p.promotion_id = r.promotion_id)
where p.promotion_id = 10340;

在更新oracle中使用select结果

2 个答案: