Question

如何将嵌套的xml文件加载到数据库表中？

<?xml version="1.0" ?> 
<person>
   <row>
       <name>Tom</name>
       <Address>
           <State>California</State>
           <City>Los angeles</City>
       </Address>
   </row>
   <row>
       <name>Jim</name>
       <Address>
           <State>California</State>
           <City>Los angeles</City>
       </Address>
   </row>
</person>

在这个xml中，person是表名，name是归档名，Tom是其归档值。地址是一个子表，状态和城市是地址内的两列。我想将person行插入到person表中，如果失败，请不要插入到地址表中。这个xml可能非常大。这样做的最佳解决方案是什么？

Answer 1

您可以将XML文档加载到XMLType中，然后查询它，例如：

DECLARE
  x XMLType := XMLType(
    '<?xml version="1.0" ?> 
<person>
   <row>
       <name>Tom</name>
       <Address>
           <State>California</State>
           <City>Los angeles</City>
       </Address>
   </row>
   <row>
       <name>Jim</name>
       <Address>
           <State>California</State>
           <City>Los angeles</City>
       </Address>
   </row>
</person>');
BEGIN
  FOR r IN (
    SELECT ExtractValue(Value(p),'/row/name/text()') as name
          ,ExtractValue(Value(p),'/row/Address/State/text()') as state
          ,ExtractValue(Value(p),'/row/Address/City/text()') as city
    FROM   TABLE(XMLSequence(Extract(x,'/person/row'))) p
    ) LOOP
    -- do whatever you want with r.name, r.state, r.city
  END LOOP;
END;

Answer 2

select *  
FROM XMLTABLE('/person/row'  
         PASSING   
            xmltype('
                <person>
                   <row>
                       <name>Tom</name>
                       <Address>
                           <State>California</State>
                           <City>Los angeles</City>
                       </Address>
                   </row>
                   <row>
                       <name>Jim</name>
                       <Address>
                           <State>California</State>
                           <City>Los angeles</City>
                       </Address>
                   </row>
                </person>
            ')
         COLUMNS  
            --describe columns and path to them:  
            name  varchar2(20)    PATH './name',  
            state varchar2(20)    PATH './Address/State',  
            city  varchar2(20)    PATH './Address/City'
     ) xmlt  
;

Answer 3

CREATE OR REPLACE PROCEDURE ADDEMP
    (xml IN CLOB)
AS
BEGIN
    INSERT INTO EMPLOYEE (EMPID,EMPNAME,EMPDETAIL,CREATEDBY,CREATED)
    SELECT 
        ExtractValue(column_value,'/ROOT/EMPID') AS EMPID
       ,ExtractValue(column_value,'/ROOT/EMPNAME') AS EMPNAME
       ,ExtractValue(column_value,'/ROOT/EMPDETAIL') AS EMPDETAIL
       ,ExtractValue(column_value,'/ROOT/CREATEDBY') AS CREATEDBY
       ,ExtractValue(column_value,'/ROOT/CREATEDDATE') AS CREATEDDATE
    FROM   TABLE(XMLSequence( XMLType(xml))) XMLDUMMAY;

    COMMIT;
END;

oracle plsql：如何解析XML并插入表中

3 个答案: