Question

我对php mysql很有经验，但javascript让我摸不着头脑。我正在尝试将谷歌地图添加到我的网站，以显示我的数据库中的图片。我让静态谷歌地图工作，但由于网址字符的限制，它只会显示37个标记。我按照谷歌地图api文档中的教程，我有一个地图，将显示我的数据库中的图像的所有坐标。我的问题是，我不能为我的生活弄清楚如何将地图设置为自动中心和自动缩放以适应我的所有标记。我的地图测试网站位于maptest。我发现这个tutorial关于如何自动居中/缩放我的地图，无论我把他的代码放在哪里都会出错。这是我的地图代码，不会自动缩放/居中：

    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="content-type" content="text/html; charset=utf-8"/>
    <title>Google Maps AJAX + mySQL/PHP Example</title>
    <script src="http://maps.google.com/maps/api/js?             key=AIzaSyDnMkDkoCHNE7BG4eobjeMJdWWZtdZvzeg&sensor=false"
        type="text/javascript"></script>
    <script type="text/javascript">
    //<![CDATA[

  var customIcons = {
  restaurant: {
    icon: 'http://labs.google.com/ridefinder/images/mm_20_blue.png',
    shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
  },
  bar: {
    icon: 'http://labs.google.com/ridefinder/images/mm_20_red.png',
    shadow: 'http://labs.google.com/ridefinder/images/mm_20_shadow.png'
  }
};

function load() {
  var map = new google.maps.Map(document.getElementById("map"), {
    center: new google.maps.LatLng(42.293564,-39.07617),
    zoom: 2,
    mapTypeId: 'roadmap'
  });
  var infoWindow = new google.maps.InfoWindow;

  // Change this depending on the name of your PHP file
  downloadUrl("phpsqlajax_genxml3.php", function(data) {
    var xml = data.responseXML;
    var markers = xml.documentElement.getElementsByTagName("marker");
    for (var i = 0; i < markers.length; i++) {
      var name = markers[i].getAttribute("name");
      //var address = markers[i].getAttribute("address");
      //var type = markers[i].getAttribute("type");
      var point = new google.maps.LatLng(
          parseFloat(markers[i].getAttribute("lat")),
          parseFloat(markers[i].getAttribute("lng")));
      var html = "<b>" + name + "</b> <br/>";
      //var icon = customIcons[type] || {};
      var marker = new google.maps.Marker({
        map: map,
        position: point,
        //icon: icon.icon,
        //shadow: icon.shadow
      });

      bindInfoWindow(marker, map, infoWindow, html);
    }
  });
}

function bindInfoWindow(marker, map, infoWindow, html) {
  google.maps.event.addListener(marker, 'click', function() {
    infoWindow.setContent(html);
    infoWindow.open(map, marker);
  });
}

function downloadUrl(url, callback) {
  var request = window.ActiveXObject ?
      new ActiveXObject('Microsoft.XMLHTTP') :
      new XMLHttpRequest;

  request.onreadystatechange = function() {
    if (request.readyState == 4) {
      request.onreadystatechange = doNothing;
      callback(request, request.status);
    }
  };

  request.open('GET', url, true);
  request.send(null);
}

function doNothing() {}

   //]]>
  </script>
 </head>

  <body onload="load()">
   <div id="map" style="width: 600px; height: 400px"></div>
    </body>
   </html>

Answer 1

试过这个？

var fitToMarkers = function(markers) {
    var bounds = new google.maps.LatLngBounds();
    var length = markers.length;
    for (var i = 0; i < length; i++) {
        bounds.extend(new google.maps.LatLng(markers[i].lat, markers[i].lng));
        map.fitBounds(bounds);
    }
};

自动缩放/中心谷歌地图API？

1 个答案: