Question

NSMutableString *str =@"abcdefg123";

我希望将每个字符随机添加到一个新的字符串，如@“f1ad2g3be2”。

Answer 1

NSMutableString *str1 = [[NSMutableString alloc]initWithString:str];
NSMutableString *str2 = [[NSMutableString alloc] init];
while ([str1 length] > 0) {
    int i = arc4random() % [str1 length];
    NSRange range = NSMakeRange(i,1);
    NSString *sub = [str1 substringWithRange:range];
    [str2 appendString:sub];
    [str1 replaceOccurrencesOfString:sub withString:@"" options:nil range:range];
}

[str1 release];

str2就是你想要的

Answer 2

非常简单。首先，您必须将字符拆分为数组才能使用。然后你多次交换字母X，我选择这样做，这样每个角色都会被交换

NSString *str =@"abcdefg123";
int length = str.length;
NSMutableArray *letters = [[NSMutableArray alloc] init];
for (int i = 0; i< length; i++) {
    NSString *letter = [NSString stringWithFormat:@"%c", [str characterAtIndex:i]];
    [letters addObject:letter];
}

for (int i = 0; i<length; i++) {
    int value = arc4random() % (length-1);
    NSLog(@"Value is : %i", value);
    [letters exchangeObjectAtIndex:i withObjectAtIndex:value];
}

NSString *results = [letters componentsJoinedByString:@""];
NSLog(@"The string before : %@", str);
NSLog(@"This is the string now : %@", results);

如何随机排序NSString

2 个答案: