Question

我正在开发一个迁移项目，需要将以下Oracle查询转换为SQL Server等效项。

select SYS_CONNECT_BY_PATH (b.actionnr,'/') as FATHER, SYS_CONNECT_BY_PATH (b.actionnr,'     | ') as REFPATH, LEVEL, 
(select count(p.refactionnr) from zisjob.zj_action p where p.refactionnr=b.actionnr)
Childs, b.* from 
( select NVL(x.ANZFiles,0) ANZFiles, act.actionnr, act.refactionnr, act.lfno, act.jobnr,     act."TYPE", act.actiontype
from zisjob.zj_action act, zisjob.zj_actiontype t, 
( select f.lno, count(f.filenr) as ANZFiles from zisjob.zj_file f where f.lno != f.lfno     Group by f.lno )x
where act.lfno=10 and act.actiontype = t.typeid(+) and act.actionnr = x.lno(+) )
b start with b.actionnr in 
(select b.actionnr from zisjob.zj_action b where b.lfno = 10 and b.refactionnr is    null)
connect by nocycle prior b.actionnr=b.refactionnr order by 1 desc, 2 asc

我正在使用CTE来做到这一点。到目前为止，我已经提出了以下内容：

with h$cte as 
(
   select
      cast (convert(varchar,b.actionnr)+'/' as varchar(max)) as FATHER,
      cast(convert(varchar,b.actionnr)+' | ' as varchar(max)) as REFPATH,
      1 as LEVEL,
      --cast (row_number() over (order by @@spid) as varchar(max)) as LEVEL,
      (select count(p.refactionnr) from zisjob.zj_action p 
       where p.refactionnr = b.actionnr) Childs, 
      b.* 
   from
     (select 
         isnull(x.ANZFiles, 0) ANZFiles, act.actionnr, act.refactionnr, act.lfno,  
         act.jobnr, act."TYPE", act.actiontype
      from zisjob.zj_action act 
      left outer join zisjob.zj_actiontype t on act.actiontype = t.typeid 
      left outer join
          (select f.lno, count(f.filenr) as ANZFiles 
           from zisjob.zj_file f
           where f.lno != f.lfno Group by f.lno ) x on act.actionnr = x.lno
      where act.lfno = 10) b
where 
   b.actionnr in
       (select b.actionnr from zisjob.zj_action b 
        where b.lfno = 10 and b.refactionnr is null)

UNION ALL

select
    CAST(FATHER + '/'+ b.ACTIONNR as varchar(max)) as FATHER,
    CAST(REFPATH + '|'+b.ACTIONNR AS VARCHAR(MAX)) as REFPATH,
    h$cte.LEVEL + 1 as LEVEL,
    (select count(p.refactionnr) from zisjob.zj_action p  
     where p.refactionnr = b.actionnr) Childs, 
    b.*
from
   (select isnull(x.ANZFiles, 0) ANZFiles, act.actionnr, act.refactionnr, 
           act.lfno, act.jobnr, act."TYPE", act.actiontype
    from zisjob.zj_action act 
    left outer join zisjob.zj_actiontype t on act.actiontype = t.typeid 
    left outer join
        (select f.lno, count(f.filenr) as ANZFiles from zisjob.zj_file f
         where f.lno != f.lfno Group by f.lno) x on act.actionnr = x.lno
    where act.lfno = 10) b, 
    h$cte
where 
    b.actionnr in
        (select b.actionnr from zisjob.zj_action b 
         where b.lfno = 10 and b.refactionnr is null)
    and h$cte.ACTIONNR = h$cte.REFACTIONNR
)
select <columns> from h$cte

翻译的查询提供以下错误：

Msg 467，Level 16，State 1，Line 1
   GROUP BY，HAVING或聚合函数不允许在递归公用表表达式'h $ cte'的递归部分中。

Msg 462，Level 16，State 1，Line 1
  递归公用表表达式“h $ cte”
的递归部分中不允许外部联接

我该如何解决这个问题？任何形式的任何帮助非常感谢。提前谢谢。

Answer 1

我终于解决了这个问题：

WITH dummy AS(

select isnull(x.ANZFiles,0) ANZFiles, act.actionnr, act.refactionnr, act.lfno, act.jobnr, act."TYPE", act.actiontype

from zisjob.zj_action act left outer join zisjob.zj_actiontype t on act.actiontype = t.typeid left outer join 

( select f.lno, count(f.filenr) as ANZFiles from zisjob.zj_file f 

where f.lno != f.lfno Group by f.lno )x on act.actionnr = x.lno

where act.lfno=10), 

 dummy2 as(

select count(p.refactionnr) as Childs 

from zisjob.zj_action p inner join dummy b on p.refactionnr=b.actionnr

),

h$cte as(

select 

cast ('/'+convert(varchar,b.actionnr) as varchar(max)) as FATHER, 

cast(' | '+convert(varchar,b.actionnr) as varchar(max)) as REFPATH, 

1 as LEVEL,

c.Childs,

--cast (row_number() over (order by @@spid) as varchar(max)) as LEVEL, 

b.* 

from dummy b, dummy2 c

where b.actionnr in 

(select b.actionnr from zisjob.zj_action b where b.lfno = 10 and b.refactionnr is null)

UNION ALL

select

CAST(FATHER + '/'+ b.ACTIONNR as varchar(max)) as FATHER,

CAST(REFPATH + '|'+b.ACTIONNR AS VARCHAR(MAX)) as REFPATH,

h$cte.LEVEL + 1 as LEVEL,c.Childs,

b.*

from dummy b, dummy2 c, h$cte

where b.actionnr in 

(select b.actionnr from zisjob.zj_action b where b.lfno = 10 and b.refactionnr is null)

and h$cte.ACTIONNR = h$cte.REFACTIONNR

)

select * from h$cte

由于我不允许在CTE的递归成员中写入外连接和GROUP BY，HAVING或聚合函数，所以我在新CTE下将其移到了外面。这就像一个魅力。

干杯!!!

Answer 2

我通过创建数据库函数解决了这个问题

创建一个像＆＃34; ufn_GetParentPath＆＃34; 这样的函数，而不是＆＃34; SYS_CONNECT_BY_PATH＆＃34; 传递ID作为参数。

CREATE FUNCTION [dbo].[ufn_GetParentPath] ( @pCurrentNodeID    INT )
RETURNS VARCHAR(1000)
AS
BEGIN

DECLARE @vCurrentNodeName     VARCHAR(50)
DECLARE @vParentID            INT

IF @pCurrentNodeID IS NULL OR @pCurrentNodeID = 0
    RETURN NULL

SELECT @vCurrentNodeName = [Name], @vParentID = [ParentID]
FROM [dbo].[Hierarchy]
WHERE [ID] = @pCurrentNodeID

RETURN ISNULL([dbo].[ufn_GetParentPath] ( @vParentID ) + '/', '') + @vCurrentNodeName

END
GO

SQL Server中的SYS_CONNECT_BY_PATH

2 个答案: