Ruby delete_if多个值 - 只删除第一个值

Question

words.delete_if do |x|
  x == ("a"||"for"||"to"||"and")
end

words是一个包含很多单词的数组。我的代码是删除“a”但不删除“for”，“to”或“and”。

Answer 1

愿这会帮到你

words.delete_if do |x|
  %w(a for to and).include?(x)
end

Answer 2

只做

words - ["a", "for", "to", "and"]

实施例

words = %w(this is a just test data for array - method and nothing)
 => ["this", "is", "a", "just", "test", "data", "for", "array", "-", "method", "and", "nothing"] 
words = words - ["a", "for", "to", "and"]
 => ["this", "is", "just", "test", "data", "array", "-", "method", "nothing"] 

Answer 3

如果你跑步＆＃34; a＆＃34; || ＆＃34; B＆＃34;在irb然后你将永远得到＆＃34; a＆＃34;因为它是一个非空值，它将由||返回总是.. 在你的情况下＆＃34; a＆＃34; ||＆＃34;对于＆＃34;将始终评估＆＃34; a＆＃34;不管数组中的其他值如何.. 所以这是我对你的问题的替代解决方案

w =％W {a for to end}

words.reject！ {| x | w.include？（x）}