代码:
<?php
session_start();
$_SESSION['msg'] = "";
$con = mysql_connect('localhost','me','omglol');
mysql_select_db('test',$con);
$q = mysql_query(sprintf("select * from UserTable where (nick=\"%s\") AND (pass=SHA1(\"%s\"))",$_POST['nick'],$_POST['pass']),$con) or die(mysql_error());
这对我来说是正确的。是的,我知道'测试'存在。并包含UserTable。
首先,感谢摆脱我忘记的标签添加php4 :(
根据Laser_wizard的建议,我做了以下内容:(整个代码):
<?php
session_start();
$_SESSION['msg'] = "";
$con = mysql_connect('localhost','me','omglol');
if(!$con)
{
die("The connection to mysql server is not being made.");
}
$db = 'test';
$selected = mysql_select_db($db,$con);
if(!$selected)
{
die(sprintf("Cannot use database %s.",$db));
}
//$q = mysql_query(sprintf("select * from UserTable where (nick=\"%s\") AND (pass=SHA1(\"%s\"))",$_POST['nick'],$_POST['pass']),$con) or die(mysql_error());
$q = mysql_query("select * from UserTable",$con) or die("The query statement still isn't working");
$row = mysql_fetch_assoc($q);
$dest=0;
if(mysql_num_rows($q)==0)
{
//$testn = mysql_query(sprintf("select * from UserTable where nick=(\"%s\")",$_POST['nick']),$con);
$testn = mysql_query("select * from Category",$con) or die("The 2nd query statement still isn't working");
if(mysql_num_rows($testn)==0)
{
$_SESSION['msg'] = "Nick ".$_POST['nick']." was not found. Check spelling or <a href=\\\"register.php\\\">register</a>";
}
else
{
$_SESSION['msg'] = "Password incorrect";
}
if(isset($_SESSION['attempts']))
{
$_SESSION['attempts'] = $_SESSION['attempts'] + 1;
}
else
{
$_SESSION['attempts'] = 1;
}
mysql_free_result($q);
mysql_free_result($testn);
mysql_close($con);
$dest = 'Location:http://cs4.sunyocc.edu/~me/onestopshop/login.php';
}
else
{
$_SESSION['nick'] = $_POST['nick'];
$_SESSION['email'] = $row['email'];
mysql_free_result($q);
mysql_close($con);
$dest = 'Location:http://cs4.sunyocc.edu/~me/onestopshop/index.php';
}
header($dest);
exit();
?>
与上述相同的错误。因此$ con设置并且$ selected读取为true,所以我很困惑接下来要检查什么。我猜mysql_select_db($ db,$ con); $ testn还没有工作但仍然读得真实吗?我很困惑接下来要做什么。
答案 0 :(得分:1)
抛出一些die语句来测试连接并确保它正在设置。 除此之外,我会说你的查询行注释掉,看看是否会导致问题。
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Not connected : ' . mysql_error());
}
// make foo the current db
$db_selected = mysql_select_db('foo', $link);
if (!$db_selected) {
die ('Can\'t use foo : ' . mysql_error());
}
答案 1 :(得分:0)
如果你有PHP&gt; = 5.1.0,请忘记这些说明并使用PDO:
<?php
$conn = new PDO('mysql:host=localhost;dbname=test', 'user', 'pass');
foreach($conn->query('SELECT * from TEST') as $row) {
print_r($row);
}
?>