在cakephp中将表添加到自定义查询中

时间:2012-10-18 15:09:01

标签: cakephp

我试图在cakephp中复制以下查询:

SELECT *
FROM uploads, proposals
WHERE proposals.id = uploads.proposal_id AND proposals.tender_id = 10

我使用上传模型中的find方法,条件如下:

$conditions = array(
  'Proposal.id' => $id,
  'AND' => array(
    'Upload.proposal_id' => 'Proposal.id'
  )
);
return($this->find('list', array('conditions' => $conditions)));

但我正在改变此查询

SELECT `Upload`.`id`, `Upload`.`title` 
FROM `kumalabs_lic`.`uploads` AS `Upload` 
WHERE `Proposal`.`id` = 10 AND `Upload`.`proposal_id` = 'Proposal.id' 

如您所见,提案表缺失,有人可以解释我如何进行此查询?

谢谢:)

3 个答案:

答案 0 :(得分:1)

我建议您使用此链接行为。它比在CakePHP中进行连接的默认方式容易得多。它适用于最新版本的CakePHP,以及1.3。

CakePHP Linkable Behavior

然后,您可以修改您的查找,如下所示:

return($this->find('list', array(
    'link' => array('Proposal'),
    'conditions' => array(
            'Proposal.id' => $id,
    ),
    'fields' => array(
            'Upload.*',
            'Proposal.*',
    ),
)));

CakePHP将自动加入您的主键/外键,因此无需使用

'Upload.proposal_id' => 'Proposal.id'

条件。

虽然你不需要这种条件,但我也想指出你做错了。这就是你在CakePHP中做AND和OR的方法

        'conditions' => array(
                'and' => array(
                    'field1' => 'value1', // Both of these conditions must be true
                    'field2' => 'value2'
                ),
                'or' => array(
                    'field1' => 'value1', // One of these conditions must be true
                    'field2' => 'value2'
                ),
        ),

答案 1 :(得分:0)

我不熟悉JOIN语法,但我相信它等于:

SELECT *
FROM uploads
INNER JOIN proposals ON proposals.id = uploads.proposal_id
WHERE proposals.tender_id = 10

...所以你需要类似的东西:

// Untested
$conditions = array(
    'Proposal.id' => $id,
    'joins' => array(
        array(
            'alias' => 'Proposal',
            'table' => 'proposals',
            'type' => 'INNER',
            'conditions' => 'Proposal.id = Upload.proposal_id',
        ),
    ),
);

当然,这是您JOIN的直接翻译。如果您的模型正确相关,则应该自动完成。

答案 2 :(得分:0)

如果模型有关联,CakePHP会自动通过'contain'关键字加入表格。试试下面的代码:

public function getProposalsFromTender($id){
   $data = $this->find('all', array(
      'conditions' => array('Proposal.id' => $id),
      'fields' => array('Upload.*', 'Proposal.*'),
      'contain' => array('Proposal')
  ));
  return($data);
}

注意: CakePHP使用显式连接而不是像...from proposals, uploads...

这样的隐式连接