Question

如何获得所需的输出？

输入字符串：

 " software Company(1920 of 2012)(sb.2)(sb.3) IBM on established (2009)"

要搜索的字词 -

"software company(1920 of 2012)"

输出

*software Company(1920 of 2012)*(sb.2)(sb.3) IBM on established (2009)

简而言之，我必须找到一个短语并用星号（*）开头和结尾替换相同的短语，忽略案例和匹配精确世界我

Answer 1

您可以使用String#replaceAll()

轻松完成此操作

String original =  " software Company(1920 of 2012)(sb.2)(sb.3) IBM on established (2009)";
String subString = "software company(1920 of 2012)";
System.out.println("New String is: " + original.replaceAll("(?i)" + Pattern.quote(subString), "*$0*"));

添加(?i)使其不区分大小写，Pattern#quote()用于转义子字符串中的特殊正则表达式字符。

打印：

New String is:  *software Company(1920 of 2012)*(sb.2)(sb.3) IBM on established (2009)

Answer 2

正则表达式将满足您的需求，请查看以下链接regular expression tutorial

如何用星号替换开头和结尾

2 个答案: