目标
我想按下GUI上的按钮并从远程计算机读取seclog.log文件(symantec AV日志),并将日志内容显示在应用程序的富文本框中。
有效的方法
除了阅读日志文件之外的一切错误消息
System.IO.IOException was unhandled
Message=The process cannot access the file '\\HOSTNAME\C$\Program Files (x86)\Symantec\Symantec Endpoint Protection\seclog.log' because it is being used by another process.
Source=mscorlib
码
//possible seclog paths
String seclogPath1 = @"\\\\" + target + "\\C$\\Program Files (x86)\\Symantec\\Symantec Endpoint Protection\\seclog.log";
String seclogPath2 = @"\\\\" + target + "\\C$\\Program Files\\Symantec\\Symantec Endpoint Protection\\seclog.log";
//if seclog exists
if (File.Exists(seclogPath1))
{
//output.AppendText("file exists at " + seclogPath1);
//var seclogContent = File.Open(seclogPath1, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
Stream stream = File.OpenRead(seclogPath1);
StreamReader streamReader = new StreamReader(stream);
string str = streamReader.ReadToEnd();
output.AppendText(str);
streamReader.Close();
stream.Close();
}
我尝试过的事情
File is being used by another process
C# The process cannot access the file ''' because it is being used by another process
Google搜索问题
以多种方式使用文件流
答案 0 :(得分:32)
//possible seclog paths
String seclogPath1 = @"\\\\" + target + "\\C$\\Program Files (x86)\\Symantec\\Symantec Endpoint Protection\\seclog.log";
String seclogPath2 = @"\\\\" + target + "\\C$\\Program Files\\Symantec\\Symantec Endpoint Protection\\seclog.log";
//if seclog exists
if (File.Exists(seclogPath1))
{
//output.AppendText("file exists at " + seclogPath1);
//var seclogContent = File.Open(seclogPath1, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
Stream stream = File.Open(seclogPath1, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
//File.OpenRead(seclogPath1);
StreamReader streamReader = new StreamReader(stream);
string str = streamReader.ReadToEnd();
output.AppendText(str);
streamReader.Close();
stream.Close();
}
我必须改变的内容
我必须创建一个readwrite filestream
原始代码
Stream stream = File.OpenRead(seclogPath1);
StreamReader streamReader = new StreamReader(stream);
新代码
Stream stream = File.Open(seclogPath1, FileMode.Open, FileAccess.Read, FileShare.ReadWrite);
//File.OpenRead(seclogPath1);
StreamReader streamReader = new StreamReader(stream);
答案 1 :(得分:1)
using (StreamReader sr = new StreamReader(filePath, true))
{
sr.Close(); //This is mandatory
//Do your file operation
}