Question

您好，

我有一张欧洲raphael地图。现在我想绘制积分 map.i中的某些城市通过转换经度n经度来尝试在其中绘制点。但遗憾的是它正在某处绘制 else.is它就像我们应该有世界地图来绘制点？这里是我的码。

script type =“text / javascript”charset =“utf-8”＆gt;

       $(document).ready(function() {
        var rsr = Raphael('map', '631', '686');
        var attr = {
                   fill: "#C0C0C0",
                   stroke: "#666",
                   "stroke-width": 1,
                   "stroke-linejoin": "round"
               };
           var world = {};
           world.Portugal = rsr.path("56,0.133-1.32,0.527c-0.661,1.321-0.264,2.906-  0.925,4.228c-0.528,1.057-3.698,5.415-3.434,6.868c0.132,0.526,1.056-0.529,1.584-0.529c0.792-0.132,1.585,0.133,2.377,0c0.396,0,0.792-0.396,1.188-0.264

c2.113,0.527,8.981,5.019,9.906,4.887c0.396,0,4.49-1.981,4.754-2.113C57.876,621.536,58.537,621.536,59.197,621.536L59.197,621.536 。Z“）ATTR（ATTR）; world.Spain = rsr.path（“M194.57,552.728c0.924,0.396,1.981,0.63.434,4.754c-，0,0.792,0 c0.661,0.133,1.453,0.133,1.849,0.528c0.66， 0.528,0.264,1.717,0.924,2.113v0.132C190.74,552.066,190.476,553.916,194.57,552.728 L194.57,552.728z“）ATTR（ATTR）;

   var current = null;
            for(var country in world) {
             (function (st, country) {
               country = country.toLowerCase();
                 st[0].style.cursor = "pointer";
                 st[0].onmouseover = function () { 
                     st.animate({fill:"#808080", stroke: "#ccc"}, 500);
                 };
                 st[0].onmouseout = function () {
                     st.animate({fill: "#C0C0C0", stroke: "#666"}, 500);
                     st.toFront();
                     R.safari();
                 };
                 st[0].onclick = function () {
                 st.toFront();
                       st.animate({
                         fill: '#808080',
                         transform: 's1.5 '
                     }, 1000);
                 };
             })(world[country], country);
           }
         });   
  var cities = {};//here i define the cities with lat n long but both draws in thesame point all time
        cities.rome = plot(55.70466,13.19101,1);
      cities.copenhagen = plot(55.676097,12.568337,1);
        var city_attr = {
                fill:"#FF7F50",
                 stroke:"#666",
                opacity: .3
            };
        function plot(lat,lon,size) {
            size = size * .5 + 4;
            return   rsr.circle(lon2x(lon),lat2y(lat),size).attr(city_attr);
          }

        function lon2x(lon) {
            var xfactor = 1.5255;
            var xoffset = 263.58;
            var x = (lon * xfactor) + xoffset;
            return x;           }           function lat2y(lat) {
             var yfactor = -1.5255;
                var yoffset = 130.5;
                var y = (lat * yfactor) + yoffset;
                return y;           }
     }); 
      var myMarker = rsr.ellipse(513.859,35.333, 7, 7).attr({
          stroke: "none", 
          opacity: .7, 
          fill: "#f00"
        });

Answer 1

地图编码的坐标似乎相当随意。如果是这样，则没有[简单]方法自动确定映射。我建议在它自己的坐标系中使用矢量图像的边界框，并在常规地图上的纬度/经度坐标中找到相应的边界框，并从中导出映射，至少作为第一近似值。

欧洲地图中的raphael情节点

1 个答案: