表文章存储文章id蚂蚁标题值。类似的表通过匹配article =相似的表ID来添加具有similar_id的额外文章。
我最好显示输出,很难用文字解释:
Article with id 3 -> Title3 Text3
when
Similar articles -> Title1(voteup,votedown), Title2(voteup,votedown)
因为文章表id =类似的表id。 (3 = 3 [similar_id 1],3 [similar_id 2]。) 并且可能当文章输出类似的文章ID时,它必须返回并从第一个表中获取similar_id的标题。
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Table Articles:
ID Title text
1 title1 text1
2 title2 text2
3 title3 text3
Table Similar:
ID Similar_ID voteup votedown
1 2 50 2
2 3 1621 531
3 1 ... ...
3 2 ... ...
答案 0 :(得分:1)
根据您的要求,Similar_ID
字段在此处是红色鲱鱼,不应包含在查询中:
SELECT articles.Title, similar.VoteUp, similar.VoteDown
FROM articles
JOIN similar ON articles.ID = similar.ID
WHERE articles.ID = 3
要包含类似的标题(虽然我不太确定您希望如何构建数据),但您可以这样做:
SELECT articles.Title, similar.VoteUp, similar.VoteDown, similar_articles.Title AS SimilarTitle
FROM articles
JOIN similar ON articles.ID = similar.ID
JOIN articles similar_articles ON similar.Similar_ID = similar_articles.ID
WHERE articles.ID = 3