MySQL,获得用户排名

时间:2009-08-18 13:26:14

标签: sql mysql rank

我有一个如下所示的mysql表:

id     name     points
1      john     4635
3      tom      7364
4      bob      234
6      harry    9857

我基本上想要在不选择所有用户的情况下获得个人用户排名。我只想按id选择一个用户,并获得用户排名,这取决于他们拥有的点数。

例如,通过id 3选择等级2来获取tom。

干杯

EEF

3 个答案:

答案 0 :(得分:18)

SELECT  uo.*, 
        (
        SELECT  COUNT(*)
        FROM    users ui
        WHERE   (ui.points, ui.id) >= (uo.points, uo.id)
        ) AS rank
FROM    users uo
WHERE   id = @id

密集等级:

SELECT  uo.*, 
        (
        SELECT  COUNT(DISTINCT ui.points)
        FROM    users ui
        WHERE   ui.points >= uo.points
        ) AS rank
FROM    users uo
WHERE   id = @id

答案 1 :(得分:2)

@Quassnoi的解决方案将失败。以下是解决问题的解决方案:

SELECT *,
IF (@score=ui.points, @rank:=@rank, @rank:=@rank+1) rank,
@score:=ui.points score
FROM users ui,
(SELECT @score:=0, @rank:=0) r
ORDER BY points DESC

答案 2 :(得分:0)

 SET @rownum := 0;
 SELECT rank, score FROM ( SELECT @rownum := @rownum +1 AS rank, `score` ,`user_id`
 FROM leaderboard 
 ORDER BY  `score` DESC , `updated_timestamp` ) as result WHERE `user_id`=$user_id
 LIMIT 1