Question

道歉，因为这是一个重复的问题，但由于某些原因，我无法对我收到的答案发表任何评论，而且问题没有得到解答。

提交表单时（通过Ajax），我收到以下错误消息：

PHP警告： mysqli_query() [function.mysqli-query]：第32行/home1/xenongro/public_html/testing/enrolment/thanks.php中的空查询

我怀疑它与if / else语句有关，但不确定实际问题是什么。作为测试，我删除了if / else语句并成功提交了表单中的一些值。不幸的是，当我有条件的时候，它出现了上述错误。

有人可以帮忙吗？

<?php

$firstname = htmlspecialchars(trim($_POST['fname']));
$lastname = htmlspecialchars(trim($_POST['lname']));
$worktel = htmlspecialchars(trim($_POST['worktel']));
$funding = htmlspecialchars(trim($_POST['funding']));
$level = htmlspecialchars(trim($_POST['level']));

$dbc = mysqli_connect('localhost', 'xxxxx', '<xxxx>', 'xxxx')
or die ('Could not connect to MySQL server.');

if ($level != "IOSH Managing Safely"){
    if ($funding == "Self Funding"){
        $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
        "VALUES ('$firstname', '$lastname', '$worktel')";
    }
    else if ($funding == "Employer Funding"){
        $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
        "VALUES ('$firstname', '$lastname', '$worktel')";
    }
}
else if ($level == "IOSH Managing Safely"){
    if ($funding == "Self Funding"){
        $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
        "VALUES ('$firstname', '$lastname', '$worktel')";
    }
    else if ($funding == "Employer Funding"){
        $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
        "VALUES ('$firstname', '$lastname', '$worktel')";
    }
}

$result = mysqli_query($dbc, $query)
or die ('error querying database');
mysqli_close($dbc);

?>

Answer 1

因为你正在使用else，如果在else if块中执行查询并在注释中恢复

$result = mysqli_query($dbc, $query) //Inside the else if block

Answer 2

如果您通过ajax发布并使用jquery，您应该首先提交这样的内容，否则它不会将任何帖子值带到ajax网址

$.ajax ({
        type:'post',
        url:"domainPath",
        success: function(response) {
            if(!response.trim()) { ....

Answer 3

如果$funding不等于“自我资助”和“雇主资助”，则$query将为空。
否则$query不能为空。

Answer 4

尝试此解决方案（在$ ErrorsRow中，您可以解决所有表单错误）：

if(isset($_POST['submit_button'])){
    $Data = $_POST;
    foreach ($Data as $key => $value) {
        if(!empty($value)) {
            $DataRow[$key] = htmlspecialchars(trim($value));
        } else {
            $ErrorsRow[] = 'Empty field '. $key;
        }
    }

    if($DataRow && !isset($ErrorsRow)){
        $firstname = $DataRow['fname'];
        $lastname  = $DataRow['lname'];
        $worktel   = $DataRow['worktel'];
        $funding   = $DataRow['funding'];
        $level     = $DataRow['level'];

    $dbc = mysqli_connect('localhost', 'xxxxx', '<xxxx>', 'xxxx')
    or die ('Could not connect to MySQL server.');

    if ($level != "IOSH Managing Safely"){
     if ($funding == "Self Funding"){
      $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
    "VALUES ('$firstname', '$lastname', '$worktel')";
    }
    else if ($funding == "Employer Funding"){
    $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
    "VALUES ('$firstname', '$lastname', '$worktel')";
    }
    }
    else if ($level == "IOSH Managing Safely"){
    if ($funding == "Self Funding"){
    $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
    "VALUES ('$firstname', '$lastname', '$worktel')";
    }
    else if ($funding == "Employer Funding"){
    $query = "INSERT INTO enrolments (fname, lname, worktel)" . 
    "VALUES ('$firstname', '$lastname', '$worktel')";
        }
        }
    if(isset($query)) {
        $result = mysqli_query($dbc, $query) or die ('error querying database');
        mysqli_close($dbc);
    }


    } else {
        if(isset($ErrorsRow) && !empty(implode($ErrorsRow))){
            $Errors = implode(',', $ErrorsRow);
            echo 'some error message'. $Errors; 
        }

    } 
}

提交表单时出现空查询错误

4 个答案: