Question

我需要编写一个sql查询，返回两个给定日期之间的工作日数（周一至周五）。

我想知道最有效的方法是什么？

SELECT           --Start with total number of days including weekends             
(DATEDIFF(dd,@StartDate,@EndDate)+1) --Subtact 2 days for each full weekend 
(DATEDIFF(wk,@StartDate,@EndDate)*2) --If StartDate is a Sunday, Subtract 1          
ELSE 0               END)            --If EndDate is a Saturday, Subtract 1 
FROM dual

然后能够从圣诞节和拳击日等计算中删除假期也很有帮助。

任何想法？

Answer 1

这很简单：

    SQL> Select count(*)
      2  from ( select rownum rnum
      3          from all_objects
      4        where rownum <= to_date('18-dec-2009','dd-mon-yyyy') - 
    to_date('16-nov-2009')+1 )
      5    where to_char( to_date('16-nov-2009','dd-mon-yyyy')+rnum-1, 'DY' )
      6                not in ( 'SAT', 'SUN' )


      COUNT(*)
    ----------
            25

    SQL> Select to_char( to_date('16-nov-2009','dd-mon-yyyy')+rnum-1, 'DY dd-mon-yyyy' )
      2  from ( select rownum rnum
      3          from all_objects
      4        where rownum <= to_date('18-dec-2009','dd-mon-yyyy') - to_date('16-nov-2009')+1 )
      5    where to_char( to_date('16-nov-2009','dd-mon-yyyy')+rnum-1, 'DY' )
      6                not in ( 'SAT', 'SUN' )


DAY_DATE
---------------
MON 16-nov-2009
TUE 17-nov-2009
WED 18-nov-2009
THU 19-nov-2009
FRI 20-nov-2009
MON 23-nov-2009
TUE 24-nov-2009
WED 25-nov-2009
THU 26-nov-2009
FRI 27-nov-2009
MON 30-nov-2009
TUE 01-dec-2009
WED 02-dec-2009
THU 03-dec-2009
FRI 04-dec-2009
MON 07-dec-2009
TUE 08-dec-2009
WED 09-dec-2009
THU 10-dec-2009
FRI 11-dec-2009
MON 14-dec-2009
TUE 15-dec-2009
WED 16-dec-2009
THU 17-dec-2009
FRI 18-dec-2009

25 rows selected.

Answer 2

计算2个日期之间工作日数的简便方法是：

SELECT
date1,
date2,
((date2-date1)-2*FLOOR((date2-date1)/7)-DECODE(SIGN(TO_CHAR(date2,'D')-
    TO_CHAR(date1,'D')),-1,2,0)+DECODE(TO_CHAR(date1,'D'),7,1,0)-
    DECODE(TO_CHAR(date2,'D'),7,1,0))*24 as WorkDays
FROM
  tablename
ORDER BY date1,date2

Answer 3

这是一个例子

with given_days(d) as(
  select <<start_date>> + level - 1
    from dual
  connect by level < = (<<end_date>> - <<start_date>>) + 1
)
select count(*)
  from given_days
where to_char(d, 'DY', 'NLS_DATE_LANGUAGE=english') not in ('SUN', 'SAT')

示范

HR\XE> with given_days as(
  2    select (to_date('&&1', 'dd.mm.yyyy') + level - 1) as g_day
  3      from dual
  4    connect by level < = (to_date('&2', 'dd.mm.yyyy') - to_date('&&1', 'dd.mm.yyyy')) + 1
  5  )
  6  select count(g_day) as cnt
  7    from given_days
  8  where to_char(g_day, 'DY', 'NLS_DATE_LANGUAGE=english') not in ('SUN', 'SAT');
Enter value for 1: 10.10.2012
old   2:   select to_date('&&1', 'dd.mm.yyyy') + level - 1
new   2:   select to_date('10.10.2012', 'dd.mm.yyyy') + level - 1
Enter value for 2: 17.10.2012
old   4:   connect by level < = (to_date('&2', 'dd.mm.yyyy') - to_date('&&1', 'dd.mm.yyyy')) + 1
new   4:   connect by level < = (to_date('17.10.2012', 'dd.mm.yyyy') - to_date('10.10.2012', 'dd.mm.yyyy')) + 1

  cnt                                                                     
----------                           
   6

Answer 4

可以通过以下方式实现：

select  SUM(decode ( to_CHAR((sysdate-ROWNUM),'DY'),'SUN',0,'SAT',0,1)) from all_objects where rownum < sysdate -  (sysdate -9)

Answer 5

你去......

首先检查假期表中有多少天，不包括周末。

在两个日期之间获取工作日（MON到FRI），然后减去假期。

create or replace
FUNCTION calculate_business_days (p_start_date IN DATE, p_end_date IN DATE)
        RETURN NUMBER IS
        v_holidays     NUMBER;
        v_start_date   DATE   := TRUNC (p_start_date);
        v_end_date     DATE   := TRUNC (p_end_date);
        BEGIN
        IF v_end_date >= v_start_date
        THEN
                SELECT COUNT (*)
                INTO v_holidays
                FROM holidays
                WHERE day BETWEEN v_start_date AND v_end_date
                AND day NOT IN (
                        SELECT hol.day 
                        FROM holidays hol 
                        WHERE MOD(TO_CHAR(hol.day, 'J'), 7) + 1 IN (6, 7)
                );

        RETURN   GREATEST (NEXT_DAY (v_start_date, 'MON') - v_start_date - 2, 0)
             +   (  (  NEXT_DAY (v_end_date, 'MON')
                     - NEXT_DAY (v_start_date, 'MON')
                    )
                  / 7
                 )
               * 5
             - GREATEST (NEXT_DAY (v_end_date, 'MON') - v_end_date - 3, 0)
             - v_holidays;
        ELSE
                RETURN NULL;
        END IF;
END calculate_business_days;

之后你可以测试一下，如：

    select 
            calculate_business_days('21-AUG-2013','28-AUG-2013') as business_days 
    from dual;

Answer 6

这就是我这样做的方式，假设你已经有了一个带有列表的日历表，表明一天是否工作日：在您的日历表中添加一个新列，例如workday_num，并使用

使用正在运行的数字填充一次

sum(case when workingday then 1 else 0 end)
over (order by calendardate rows unbounded preceding)

现在它是你的日历的两个连接，以及p_start_date和p_end_date的workday_nums的简单区别。

SQL返回日期中传递的2个工作日数

6 个答案: