如何使这个If语句跳到下面的if语句?如果那么我试过了,但是它不起作用。无论是否将输入传递给变量,我都希望它显示。
declare @sql varchar(8000)
declare @sql_where varchar(8000)
declare @ww varchar(10)
declare @plant varchar(10)
declare @plnr_id varchar(10)
set @plant = 'CS58'
set @ww = '201240'
set @plnr_id = 'G37'
set @sql_where = 'where'
set @sql = 'select * from rout_sub_doi '
if len(@plant) > 0
set @sql_where = @sql_where + ' plant = ''' + @plant + ''' '
if len(@ww) > 0
set @sql_where = @sql_where + 'AND sys_intel_ww = ''' + @ww + ''' '
if len(@plnr_id) > 0
set @sql_where = @sql_where + ' AND plnr_id = ''' + @plnr_id + ''' '
print @sql
print @sql_where
exec (@sql + @sql_where )
答案 0 :(得分:0)
处理未知数量的条件的常用方法是,当已知id不可为空时,将WHERE 1=1
或其他内容设为良性,例如WHERE id IS NOT NULL
。
declare @sql varchar(8000)
declare @sql_where varchar(8000)
declare @ww varchar(10)
declare @plant varchar(10)
declare @plnr_id varchar(10)
set @plant = 'CS58'
set @ww = '201240'
set @plnr_id = 'G37'
set @sql_where = ''
set @sql = 'select * from rout_sub_doi where 1=1 '
if len(@plant) > 0
set @sql_where = @sql_where + 'AND plant = ''' + @plant + ''' '
if len(@ww) > 0
set @sql_where = @sql_where + 'AND sys_intel_ww = ''' + @ww + ''' '
if len(@plnr_id) > 0
set @sql_where = @sql_where + 'AND plnr_id = ''' + @plnr_id + ''' '
print @sql
print @sql_where
exec (@sql + @sql_where )