Question

我有这样的JSON：

[{
"username":"bitu","password":"123456", "id":"1"
},
{
"username":"admin","password":"admin", "id":"2"
},
{
"username":"demo","password":"demo", "id":"3"
},
{
"username":"admin","password":"admin", "id":"8"
},
{
"username":"admin","password":"admin", "id":"5"
}]

我想将NSMutableArray用于获取"id"。我怎么能这样做？请帮帮我！

Answer 1

NSLog(@"%@",[[yourArray objectAtIndex:index] valueForKey:@"id"]);

Answer 2

从objectAtIndex

获取valueForKey和NSMutableArray的价值

NSString *UserName = [[yourArray objectAtIndex:index] valueForKey:@"username"];//if you required
NSString *Password = [[yourArray objectAtIndex:index] valueForKey:@"password"];//if you required
NSString *UID = [[yourArray objectAtIndex:index] valueForKey:@"id"];

：）

Answer 3

NSMutableArray *idArray = [[NSMutableArray alloc] init];

    for (NSDictionary *obj in yourJsonArray) {
        [idArray addObject:[obj objectForKey:@"id"]];
    }
NSLog(@"%@",idArray);

Answer 4

让NSArray * info数组包含您的数据。在这里，我将检索您的数据并将其保存在NSMutableArray名称，密码和ID中。

在viewDidLoad方法中将这些数组初始化为

   NSMutableArray name=[[NSMutableArray alloc] init]; 
   NSMutableArray password=[[NSMutableArray alloc] init]; 
   NSMutableArray id=[[NSMutableArray alloc] init];

在重新审阅JSON响应后使用以下代码

   NSArray *info;  // this array contains your data
   int counter=[info count];

   for(int i=0;i<counter;i++)
   {
         NSDictionary *currentObject=[info objectAtIndex:i];
         NSString *userName=[currentObject objectForKey:@"username"];
         NSString *userPassword=[currentObject objectForKey:@"password"];
         NSString *userID=[currentObject objectForKey:@"id"];
         [name addObject:userName];
         [password addObject:userPassword];
         [id addObject: userID];
   }

Answer 5

示例，Array包含字符串对象。

Acccess:
NSString.FromHandle(deviceList.ValueAt(i));

使用NSMutableArray获取对象？

5 个答案: