Question

我有两张桌子第一表：适用于产品第二个表：对于类别

我想在浏览器中显示

类别1（20）类别2（5） category3（3）

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");
  $row_num_sub = mysql_num_rows($select_num_sub);
  $smarty->assign('numb',$row_num_sub);

 $sub_cats[] = $row_sub;
}
$smarty->assign('sub_cats',$sub_cats);

Answer 1

试试这个：

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");
  $smarty->assign('numb',$row_num_sub);

 $sub_cats[] = $row_sub;
 $sub_cats['count']=mysql_num_rows($select_num_sub);
}
$smarty->assign('sub_cats',$sub_cats);

Answer 2

尝试

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");         
 $sub_cats[] = $row_sub;
 $sub_cats['count']=mysql_num_rows($select_num_sub);
}
$smarty->assign('sub_cats',$sub_cats);

然后打电话给你的聪明人：

{$ sub_cats.name}（{$ sub_cats.count}）// $ sub_cats.name应该是类别的“名称”

循环时，我无法在内部生成num行

2 个答案: