Question

我有一个SELECT语句，其中我加入了2个单独的表。

$result = mysql_query('SELECT * FROM (SELECT * FROM gslil0009) as table1 UNION SELECT * FROM (SELECT * FROM gslil0028) as table2' . ' ORDER BY lname');

while($row = mysql_fetch_array($result)) {
  echo $row['fname'];
}

如何打印出来自哪个表？

Answer 1

$result = mysql_query('SELECT *,'tbl1' FROM (SELECT * FROM gslil0009) as table1 
               UNION SELECT *,'tbl2' FROM (SELECT * FROM gslil0028) as table2' 
               . ' ORDER BY lname');

while($row = mysql_fetch_array($result)) {
  echo $row['fname'];
  echo $row['tbl1'];
}

Answer 2

我使用与sel相同的解决方案只需添加反斜杠以避免错误并为表名添加名称。

$result = mysql_query('SELECT *,\'table1\' AS tablename FROM (SELECT * FROM gslil0009) as table1 
               UNION SELECT *,\'table2\' AS tablename FROM (SELECT * FROM gslil0028) as table2' 
               . ' ORDER BY lname');

while($row = mysql_fetch_array($result)) {
  echo $row['fname'];
  echo $row['tablename'];
}

我无法在他的帖子上添加评论。

从查询中显示表名称

2 个答案: