Question

鉴于wchar_t* str;指向以null结尾的utf32（或utf16）字符串，我应该使用什么命令在lldb中打印它？

Answer 1

我假设您要将其打印为utf8。它有点牵扯 - 你需要在python中为类型创建一个摘要提供程序，它返回一个utf8字符串进行打印。但这并不是特别复杂。创建一个像~/lldb/wcharsummary.py这样的小python文件，内容如

import lldb
def wchar_SummaryProvider(valobj, dict):
  e = lldb.SBError()
  s = u'"'
  if valobj.GetValue() != 0:
    i = 0
    newchar = -1
    while newchar != 0:
      # read next wchar character out of memory
      data_val = valobj.GetPointeeData(i, 1)
      size = data_val.GetByteSize()
      if size == 1:
        newchar = data_val.GetUnsignedInt8(e, 0)    # utf-8
      if size == 2:
        newchar = data_val.GetUnsignedInt16(e, 0)   # utf-16
      if size == 4:
        newchar = data_val.GetUnsignedInt32(e, 0)   # utf-32
      else:
        return '<error>'
      if e.fail:
        return '<error>'
      i = i + 1
      # add the character to our string 's'
      if newchar != 0:
        s = s + unichr(newchar)
  s = s + u'"'
  return s.encode('utf-8')

将其加载到lldb并将此python函数设置为wchar_t *的摘要提供程序;最容易将其放入~/.lldbinit文件中以便重复使用：

command script import ~/lldb/wcharsummary.py
type summary add -F wcharsummary.wchar_SummaryProvider "wchar_t *"

然后给出一些在32位wchar_t中有一些utf32编码字符的源，

NSString *str = @"こんにちは";  // 5 characters long
wchar_t *str_utf32_wchar = (wchar_t*) [[str dataUsingEncoding:NSUTF32StringEncoding] bytes];

lldb将为我们打印utf8：

Process 22278 stopped
* thread #1: tid = 0x1c03, 0x0000000100000e92 a.out`main + 146 at a.m:11, stop reason = step over
    #0: 0x0000000100000e92 a.out`main + 146 at a.m:11
   8    
   9        NSString *str = @"こんにちは";  // 5 characters long
   10       wchar_t *str_utf32_wchar = (wchar_t*) [[str dataUsingEncoding:NSUTF32StringEncoding] bytes];
-> 11       printf ("0x%llx 0x%llx 0x%llx 0x%llx\n", (uint64_t) str_utf32_wchar[0], (uint64_t) str_utf32_wchar[1], 
   12                                                (uint64_t) str_utf32_wchar[2], (uint64_t) str_utf32_wchar[3]);
   13   
   14       [pool release];

(lldb) fr va
(NSAutoreleasePool *) pool = 0x0000000100108190
(NSString *) str = 0x0000000100001068 @"こんにちは"
(wchar_t *) str_utf32_wchar = 0x0000000100107f80 "こんにちは"

(lldb) p str_utf32_wchar
(wchar_t *) $0 = 0x0000000100107f80 "こんにちは"

(lldb) x/16b `str_utf32_wchar`
0x100107f80: 0xff 0xfe 0x00 0x00 0x53 0x30 0x00 0x00
0x100107f88: 0x93 0x30 0x00 0x00 0x6b 0x30 0x00 0x00
(lldb)

Answer 2

我已经修改了Jason的代码，直接处理wxString，而不必更改int*指针的摘要。

通过在Xcode调试器控制台中键入script命令来测试它，然后粘贴下面的代码并按ctrl-D。然后再次在lldb提示符下键入type summary add --python-function wxString_SummaryProvider "wxString"。适用于我的wxWidgets构建。

def wxString_SummaryProvider(valobj, dict):
  e = lldb.SBError()
  charPointer = valobj.GetChildMemberWithName('m_impl').GetChildMemberWithName('_M_dataplus').GetChildMemberWithName('_M_p')
  valobj = charPointer
  s = u'"'
  if valobj.GetValue() != 0:
    i = 0
    newchar = -1
    while newchar != 0:
      # read next wchar character out of memory
      data_val = valobj.GetPointeeData(i, 1)
      size = data_val.GetByteSize()
      if size == 1:
        newchar = data_val.GetUnsignedInt8(e, 0)    # utf-8
      if size == 2:
        newchar = data_val.GetUnsignedInt16(e, 0)   # utf-16
      if size == 4:
        newchar = data_val.GetUnsignedInt32(e, 0)   # utf-32
      else:
        return '<error>'
      if e.fail:
        return '<error>'
      i = i + 1
      # add the character to our string 's'
      # print "char2 = %s" % newchar
      if newchar != 0:
        s = s + unichr(newchar)
  s = s + u'"'
  return s.encode('utf-8')

如何在lldb中打印wchar_t字符串？

2 个答案: