Question

如果test = true，我想将cobertura排除在检测代码之外。

现在我在顶部提供了所有必需的声明：

require 'buildr/java/cobertura'
require 'buildr/scala'

然后每次构建运行时我都会得到：

使用cobertura数据文件检测类 C：/usr/git_workspaces/reports/cobertura.ser

这意味着我的生产代码中包含了cobertura工具。

这是我构建的下一部分

compile.with  CORE, SLF4J, LOG4J, WS_CLIENTS, JODA_TIME,
            [omitted for brevity]

compile.options.other = %w(-encoding UTF-8)

cobertura.exclude '[omitted for brevity]'

resources.filter.using *RESOURCES_FILTER

test.using :junit
# need this because of forking.  It does not appear to use the environmental variables defined above.
test.using :java_args => ["-XX:MaxPermSize=128M"]
test.with JUNIT, SCALATEST, MOCKITO, POWERMOCK, HAMCREST, SPRING.test

# Pakcage is below here but the code has already been instrumented...

compile.with编译实际发生的地方？所以我可以做一个if测试，然后添加cobertura？

Answer 1

如果你不需要“buildr / java / cobertura”那么就没有工具了。

我们'解决了'这样（至少命令行参数必须包含“cobertura”，否则这些类没有检测）

ARGV.each do |a| 
  if (a.include?("cobertura")) 
    require "buildr/java/cobertura"
    break
  end
end

你可以这样做

require_cb = ture
ARGV.each do |a|   
    if (a.include?("test=yes"))
    require_cb = false      
    break
  end
end
require "buildr/java/cobertura" if require_cb

HTH

如果test = true，我想从仪器代码中排除cobertura

1 个答案: