Question

我有一个带有“客户”信息的数据库设置。我有一个PHP表单来搜索字符串，名字（fname），姓氏（lname）和电话号码（电话）。出于某种原因，我甚至没有显示帮助器显示功能正在运行？我一遍又一遍地重读这段代码，似乎无法弄清楚我遗失的地方。

<form name="search" method="post" action="<?=$PHP_SELF?>">
 Seach for: <input type="text" name="find" /> in 
 <Select NAME="field">
 <Option VALUE="fname">First Name</option>
 <Option VALUE="lname">Last Name</option>
 <Option VALUE="phone">Phone #</option>
 </Select>
 <input type="hidden" name="searching" value="yes" />
 <input type="submit" name="search" value="Search" />
 </form>
 <? 
 //This is only displayed if they have submitted the form 
 if ($searching =="yes") 
 { 
 echo "<h2>Results</h2><p>"; 

 //If they did not enter a search term we give them an error 
 if ($find == "") 
 { 
 echo "<p>You forgot to enter a search term"; 
 exit; 
 } 

 // We preform a bit of filtering 
 $find = strtoupper($find); 
 $find = strip_tags($find); 
 $find = trim ($find); 

 //Now we search for our search term, in the field the user specified 
 $data = mysql_query("SELECT * FROM customer WHERE upper($field) LIKE'%$find%'"); 

 //And we display the results 
 while($result = mysql_fetch_array( $data )) 
 { 
 echo $result['fname']; 
 echo " "; 
 echo $result['lname']; 
 echo "<br>"; 
 echo $result['phone']; 
 echo "<br>"; 
 echo "<br>"; 
 } 

 //This counts the number or results - and if there wasn't any it gives them a little message explaining that 
 $anymatches=mysql_num_rows($data); 
 if ($anymatches == 0) 
 { 
 echo "Sorry, but we can not find an entry to match your query<br><br>"; 
 } 

 //And we remind them what they searched for 
 echo "<b>Searched For:</b> " .$find; 
 } 
 ?>

Answer 1

您的脚本中存在一些错误，我会尽力帮助您：

<? --> <?php

然后你的表单通过方法POST传递参数，所以你必须检查这样的搜索：

if ($_POST['searching'] =="yes")

你在这里遇到同样的错误：

if ($_POST['find'] == "")

在这里：

 $find = strtoupper($_POST['find']);

再见！

Answer 2

您应首先创建一个如下所示的查询字符串，然后在mysql_query内使用此字符串。希望这样做。

str = "SELECT * FROM customer WHERE upper(".$field.") LIKE'%".$find%."'";

PHP / MySQL字符串搜索查询

2 个答案: