Question

示例：我需要其中id = 1的金额之和不等于id＆lt;＆gt;的金额之和的数字。 1，连同id和差异。
表（在本例中为视图）可能如下所示：

NUMBER   AMOUNT   ID

0001     500       1
0001     500       2
0002     400       3
0003     299       1
0003     300       3
0003     300       3

非常感谢你对此的帮助。

Answer 1

使用此查询，您可以获得按编号分组的金额总和，ID等于1且ID不等于1.

SELECT NUMBER
, SUM(CASE WHEN ID = 1 THEN AMOUNT ELSE 0 END) AS Equals1
, SUM(CASE WHEN ID <> 1 THEN AMOUNT ELSE 0 END) AS NotEquals1
FROM DataTable
GROUP BY NUMBER

如果这是您所期望的，请使用以下查询来获取按编号分组的差异金额。

SELECT NUMBER, (Equals1 - NotEquals1) AS DifferenceAmount
FROM
(
    SELECT NUMBER
    , SUM(CASE WHEN ID = 1 THEN AMOUNT ELSE 0 END) AS Equals1
    , SUM(CASE WHEN ID <> 1 THEN AMOUNT ELSE 0 END) AS NotEquals1
    FROM DataTable
    GROUP BY NUMBER
) AS GroupedTable
WHERE Equals1 <> NotEquals1

Answer 2

SELECT
    MyView.Number,
    MyView.Amount - D.OverOneTotal AS Difference
FROM
    MyView
    LEFT JOIN 
    (SELECT
        Number,
        SUM(Amount) OverOneTotal
    FROM
        MyView
    WHERE
        ID > 1
    GROUP BY 
        Number) D ON MyView.Number = D.Number
WHERE
    MyView.ID = 1
    AND MyView.Amount <> D.OverOneTotal

如何根据一个表中的不同字段值减去两个总和（视图）

2 个答案: