Question

吼叫是我的cronjob脚本，我只想要

等待 3rd_job 完成 4th，5th

＆安培;等待 2nd_job 完成以启动 6,7,8th 作业。

如何提前实现这一目标

目前正在开始 4,5th 工作，它正在等待 1,2,3th 工作完成但我只想等待第3次开始 4,5th 并等待第二次完成以表明 6,7,8th

    #!/bin/bash
    cd /home/ubuntu/
    PATH=$PATH:/usr/local/bin
    export PATH
    nohup scrapy crawl 1st_job &
    nohup scrapy crawl 2nd_job &
    nohup scrapy crawl 3rd_job &
    wait $(pgrep 3rd_job)
    nohup scrapy crawl 4th_job &
    nohup scrapy crawl 5th_job &
    wait $(pgrep 2nd_job)
    nohup scrapy crawl 6th_job &
    nohup scrapy crawl 7th_job &
    nohup scrapy crawl 8th_job &

Answer 1

您可以使用包含上次生成的异步任务的PID的$!变量：

#!/bin/bash
cd /home/ubuntu/
PATH=$PATH:/usr/local/bin
export PATH
nohup scrapy crawl 1st_job &
nohup scrapy crawl 2nd_job &
pid_2nd="$!"
nohup scrapy crawl 3rd_job &
wait $!
nohup scrapy crawl 4th_job &
nohup scrapy crawl 5th_job &
wait $pid_2nd
nohup scrapy crawl 6th_job &
nohup scrapy crawl 7th_job &
nohup scrapy crawl 8th_job &

如果你想要一些更复杂的东西，例如以有向无环图方式执行（例如，一旦第3完成开始4-5，并且第二次完成开始6-8）我建议你重新组织调用函数，以便可以异步调用它们：

#!/bin/bash
second () {
    nohup scrapy crawl 2nd_job
    nohup scrapy crawl 6th_job &
    nohup scrapy crawl 7th_job &
    nohup scrapy crawl 8th_job &
}

third () {
    nohup scrapy crawl 3rd_job
    nohup scrapy crawl 4th_job &
    nohup scrapy crawl 5th_job &
}

cd /home/ubuntu/
PATH=$PATH:/usr/local/bin
export PATH
nohup scrapy crawl 1st_job &
third &
second &

希望这有助于=）

cronjob等待理解

1 个答案: